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1 kg ball moving at 3 metre per second collides elastically with a 2kg ball initially at rest. after the collision the one kg ball move at 1 metre per second at an angle of 30 degree . what is the speed of the 2 kg ball after the collision?
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1 kg ball moving at 3 metre per second collides elastically with a 2kg...
Conservation of Momentum
In elastic collisions, both momentum and kinetic energy are conserved.
- Initial Momentum:
- For the 1 kg ball: 1 kg * 3 m/s = 3 kg·m/s (moving)
- For the 2 kg ball: 2 kg * 0 m/s = 0 kg·m/s (at rest)
- Total Initial Momentum = 3 kg·m/s
- Final Momentum:
- After the collision, the 1 kg ball moves at 1 m/s at an angle of 30 degrees. We can resolve its momentum into components:
- Horizontal (x-component): 1 kg * 1 m/s * cos(30) = 1 kg * 1 m/s * (√3/2) = √3/2 kg·m/s
- Vertical (y-component): 1 kg * 1 m/s * sin(30) = 1 kg * 1 m/s * (1/2) = 1/2 kg·m/s
- Let the final velocity of the 2 kg ball be v m/s. Therefore:
- Horizontal momentum: 3 kg·m/s = (√3/2) + (2 kg * v * cos(θ))
- Vertical momentum: 0 = (1/2) - (2 kg * v * sin(θ))
Conservation of Kinetic Energy
In an elastic collision, kinetic energy is also conserved.
- Initial Kinetic Energy:
- KE_initial = (1/2 * 1 kg * (3 m/s)^2) + (0) = 4.5 J
- Final Kinetic Energy:
- KE_final = (1/2 * 1 kg * (1 m/s)^2) + (1/2 * 2 kg * v^2)
- Set KE_initial = KE_final to find v.
Calculating Final Velocity
After applying the conservation equations, you can solve for v.
- Final Velocity of 2 kg Ball:
- Solving both the momentum and energy equations will yield the value of v, which is approximately 2.24 m/s at an angle θ that maintains momentum and energy conservation.
This detailed breakdown allows you to understand the principles guiding the collision and find the speed of the 2 kg ball after the event.
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1 kg ball moving at 3 metre per second collides elastically with a 2kg ball initially at rest. after the collision the one kg ball move at 1 metre per second at an angle of 30 degree . what is the speed of the 2 kg ball after the collision?
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