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The standard redox potentials for the reactions Mn^ 2+ + 2e -> Mn and M n^ 3+ +e Mn^ 2+ are-1.18V and 1.51V respectively. What is the redox potential for the reaction M n^ 3+ + 3e - Mn?
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The standard redox potentials for the reactions Mn^ 2+ + 2e -> Mn and ...
Understanding Redox Potentials
Redox potentials indicate the tendency of a species to gain or lose electrons. In this case, we have the following standard redox potentials:
- Mn^2+ + 2e- → Mn: E° = -1.18 V
- Mn^3+ + e- → Mn^2+: E° = 1.51 V
To find the redox potential for the reaction:
Mn^3+ + 3e- → Mn
we will combine the two given half-reactions.
Combining Half-Reactions
1. The first half-reaction can be reversed to express Mn as a product:
- Mn → Mn^2+ + 2e- (E° = +1.18 V)
2. The second half-reaction remains as is:
- Mn^3+ + e- → Mn^2+ (E° = 1.51 V)
Now, we need to align these reactions. We can multiply the second half-reaction by 2 to balance the number of electrons:
- 2(Mn^3+ + e- → Mn^2+) gives us:
- 2Mn^3+ + 2e- → 2Mn^2+ (E° = 1.51 V)
Now, we can add the reversed first half-reaction and the doubled second half-reaction:
Net Reaction
- Mn + 2Mn^3+ + 2e- → 2Mn^2+ + 2e-
This simplifies to:
- Mn + 2Mn^3+ → 2Mn^2+
Calculating the Overall Potential
Using the formula:
E° = E°(oxidation) + E°(reduction)
E° = 1.51 V + 1.18 V = 2.69 V
However, since we have 3 electrons in total from the original reaction, we need to divide by 3:
Final Redox Potential
E°(Mn^3+ + 3e- → Mn) = 2.69 V / 3 = 0.8967 V
Thus, the redox potential for the reaction Mn^3+ + 3e- → Mn is approximately 0.897 V.
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The standard redox potentials for the reactions Mn^ 2+ + 2e -> Mn and M n^ 3+ +e Mn^ 2+ are-1.18V and 1.51V respectively. What is the redox potential for the reaction M n^ 3+ + 3e - Mn?
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