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The path followed by a body projected at an angle with horizontall is given by y = sqrt(3) * x - 1/2 * x ^ 2 If g = 10m / (s ^ 2) then the angle of projection of the projectile from horizontall is
(1) 30 deg
(2) 45 deg
(3) 60 deg
(4)
(?
(1) 30 deg
(2) 45 deg
(3) 60 deg
(4)
(?
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The path followed by a body projected at an angle with horizontall is ...
Understanding the Projectile Motion Equation
The path of the projectile is given by the equation:
y = sqrt(3) * x - 1/2 * x^2.
This equation describes a parabolic trajectory, where 'y' represents the vertical position and 'x' represents the horizontal position.
Identifying the Components of Motion
In the projectile motion, we can identify the following components:
- Initial Velocity (u): The initial velocity can be broken down into horizontal (u_x) and vertical (u_y) components.
- Acceleration due to Gravity (g): The downward acceleration is given as g = 10 m/s^2.
Finding the Angle of Projection
The general form of a projectile's path can also be expressed as:
y = (tanθ) * x - (g / (2 * u^2 * cos²θ)) * x²,
where θ is the angle of projection.
Comparing coefficients, we have:
- Slope (tanθ): From the given equation, the slope is sqrt(3). Therefore,
tanθ = sqrt(3), leading to θ = 60 degrees.
- Quadratic Coefficient: The coefficient of x² is -1/2, which can be related to the gravitational effect in the motion.
Conclusion
Thus, the angle of projection of the projectile from the horizontal is:
60 degrees (Option 3).
The path of the projectile is given by the equation:
y = sqrt(3) * x - 1/2 * x^2.
This equation describes a parabolic trajectory, where 'y' represents the vertical position and 'x' represents the horizontal position.
Identifying the Components of Motion
In the projectile motion, we can identify the following components:
- Initial Velocity (u): The initial velocity can be broken down into horizontal (u_x) and vertical (u_y) components.
- Acceleration due to Gravity (g): The downward acceleration is given as g = 10 m/s^2.
Finding the Angle of Projection
The general form of a projectile's path can also be expressed as:
y = (tanθ) * x - (g / (2 * u^2 * cos²θ)) * x²,
where θ is the angle of projection.
Comparing coefficients, we have:
- Slope (tanθ): From the given equation, the slope is sqrt(3). Therefore,
tanθ = sqrt(3), leading to θ = 60 degrees.
- Quadratic Coefficient: The coefficient of x² is -1/2, which can be related to the gravitational effect in the motion.
Conclusion
Thus, the angle of projection of the projectile from the horizontal is:
60 degrees (Option 3).
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The path followed by a body projected at an angle with horizontall is given by y = sqrt(3) * x - 1/2 * x ^ 2 If g = 10m / (s ^ 2) then the angle of projection of the projectile from horizontall is(1) 30 deg(2) 45 deg(3) 60 deg(4)(?
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The path followed by a body projected at an angle with horizontall is given by y = sqrt(3) * x - 1/2 * x ^ 2 If g = 10m / (s ^ 2) then the angle of projection of the projectile from horizontall is(1) 30 deg(2) 45 deg(3) 60 deg(4)(? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The path followed by a body projected at an angle with horizontall is given by y = sqrt(3) * x - 1/2 * x ^ 2 If g = 10m / (s ^ 2) then the angle of projection of the projectile from horizontall is(1) 30 deg(2) 45 deg(3) 60 deg(4)(? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The path followed by a body projected at an angle with horizontall is given by y = sqrt(3) * x - 1/2 * x ^ 2 If g = 10m / (s ^ 2) then the angle of projection of the projectile from horizontall is(1) 30 deg(2) 45 deg(3) 60 deg(4)(?.
The path followed by a body projected at an angle with horizontall is given by y = sqrt(3) * x - 1/2 * x ^ 2 If g = 10m / (s ^ 2) then the angle of projection of the projectile from horizontall is(1) 30 deg(2) 45 deg(3) 60 deg(4)(? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The path followed by a body projected at an angle with horizontall is given by y = sqrt(3) * x - 1/2 * x ^ 2 If g = 10m / (s ^ 2) then the angle of projection of the projectile from horizontall is(1) 30 deg(2) 45 deg(3) 60 deg(4)(? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The path followed by a body projected at an angle with horizontall is given by y = sqrt(3) * x - 1/2 * x ^ 2 If g = 10m / (s ^ 2) then the angle of projection of the projectile from horizontall is(1) 30 deg(2) 45 deg(3) 60 deg(4)(?.
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