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A particle is moving along a straight line with initial velocity 48 m/s and acceleration -10m/s^2.the distance travelled by it in 5th sec is?
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A particle is moving along a straight line with initial velocity 48 m/...
Understanding the Problem
To determine the distance traveled by the particle in the 5th second, we first need to use the equations of motion. The initial velocity (u) is 48 m/s, and the acceleration (a) is -10 m/s².
Key Equations
- The distance covered in the nth second can be calculated using the formula:
- S_n = u + (1/2) * a * (2n - 1)
Here, we need to find the distance for n = 5.
Calculating Distance in the 5th Second
- Substitute the values into the formula:
- u = 48 m/s
- a = -10 m/s²
- n = 5
- The distance (S_5) is calculated as follows:
- S_5 = 48 + (1/2) * (-10) * (2*5 - 1)
- S_5 = 48 + (1/2) * (-10) * 9
- S_5 = 48 - 45
- S_5 = 3 m
Conclusion
The distance traveled by the particle in the 5th second is:
- 3 meters
This calculation shows how the negative acceleration affects the distance covered by the particle as it slows down over time. Understanding these principles is crucial for solving motion-related problems in physics, especially in competitive exams like NEET.
To determine the distance traveled by the particle in the 5th second, we first need to use the equations of motion. The initial velocity (u) is 48 m/s, and the acceleration (a) is -10 m/s².
Key Equations
- The distance covered in the nth second can be calculated using the formula:
- S_n = u + (1/2) * a * (2n - 1)
Here, we need to find the distance for n = 5.
Calculating Distance in the 5th Second
- Substitute the values into the formula:
- u = 48 m/s
- a = -10 m/s²
- n = 5
- The distance (S_5) is calculated as follows:
- S_5 = 48 + (1/2) * (-10) * (2*5 - 1)
- S_5 = 48 + (1/2) * (-10) * 9
- S_5 = 48 - 45
- S_5 = 3 m
Conclusion
The distance traveled by the particle in the 5th second is:
- 3 meters
This calculation shows how the negative acceleration affects the distance covered by the particle as it slows down over time. Understanding these principles is crucial for solving motion-related problems in physics, especially in competitive exams like NEET.
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A particle is moving along a straight line with initial velocity 48 m/s and acceleration -10m/s^2.the distance travelled by it in 5th sec is?
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A particle is moving along a straight line with initial velocity 48 m/s and acceleration -10m/s^2.the distance travelled by it in 5th sec is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle is moving along a straight line with initial velocity 48 m/s and acceleration -10m/s^2.the distance travelled by it in 5th sec is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is moving along a straight line with initial velocity 48 m/s and acceleration -10m/s^2.the distance travelled by it in 5th sec is?.
A particle is moving along a straight line with initial velocity 48 m/s and acceleration -10m/s^2.the distance travelled by it in 5th sec is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle is moving along a straight line with initial velocity 48 m/s and acceleration -10m/s^2.the distance travelled by it in 5th sec is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is moving along a straight line with initial velocity 48 m/s and acceleration -10m/s^2.the distance travelled by it in 5th sec is?.
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