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log5P x logp x = 2. What is the value of x?
  • a)
    125
  • b)
    P2
  • c)
    25
  • d)
    51/2
Correct answer is option 'C'. Can you explain this answer?
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log5P x logp x = 2. What is the value of x?a)125b)P2c)25d)51/2Correct ...
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log5P x logp x = 2. What is the value of x?a)125b)P2c)25d)51/2Correct ...
This can be further expand as-logP/log5 × logx/lopP = 2
Now eliminating logP
We get logx/log5=2 log5(X)=2X=5^2=25
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Community Answer
log5P x logp x = 2. What is the value of x?a)125b)P2c)25d)51/2Correct ...
We can write this equation as (log p)/(log5)*(log x)/(log p)=2
=> (log x)/(log5) = 2
=> it can be written as (log x) base 5= 2
so, x = (5)² x=25hence C is correct.
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log5P x logp x = 2. What is the value of x?a)125b)P2c)25d)51/2Correct answer is option 'C'. Can you explain this answer?
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