NEET Exam  >  NEET Questions  >  Reaction of propanone with methyl magnesium b... Start Learning for Free
Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358
K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be
1)2-Methyl propane-1, 2-diol
2)2-Methyl propan-1-ol
3)Butan-2-one
4)2-Methyl propane-1, 3 diol?
Most Upvoted Answer
Reaction of propanone with methyl magnesium bromide followed by hydrol...
Reaction of Propanone with Methyl Magnesium Bromide
Propanone (acetone) reacts with methyl magnesium bromide (a Grignard reagent) to form a tertiary alcohol. The reaction can be outlined as follows:
- Propanone + Methyl Magnesium Bromide → Tertiary Alcohol (Compound P)
This reaction results in a compound (P) that is 2-Methylpropan-2-ol.
 
Hydrolysis of Compound (P)
The hydrolysis of the Grignard adduct leads to the cleavage of the bond between the magnesium and the oxygen, resulting in the formation of the corresponding alcohol.
- Tertiary Alcohol (Compound P) → Hydrolyzed Product
 
Treatment with 20% H3PO4 at 358 K
When compound (P) is treated with 20% H3PO4 at 358 K, it undergoes dehydration, leading to the formation of an alkene (Compound Q).
- Tertiary Alcohol (P) + H3PO4 → Alkene (Compound Q)
 
Reaction of Compound (Q) with Bayer's Reagent
Bayer’s reagent (potassium permanganate in a basic medium) is used for the oxidation of alkenes. The reaction of compound (Q) results in the formation of a diol or an alcohol, depending on the structure of Q.
- Alkene (Q) + Bayer’s Reagent → Compound (R)
 
Identification of Compound (R)
Given the structure of the initial reactants and the reactions involved, compound (R) can be deduced as follows:
- Compound (R) is likely to be 2-Methyl propane-1, 2-diol, as it forms from the oxidation of the alkene derived from the dehydration of compound (P).
Thus, the correct answer is option 1) 2-Methyl propane-1, 2-diol.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol?
Question Description
Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol?.
Solutions for Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol? defined & explained in the simplest way possible. Besides giving the explanation of Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol?, a detailed solution for Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol? has been provided alongside types of Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol? theory, EduRev gives you an ample number of questions to practice Reaction of propanone with methyl magnesium bromide followed by hydrolysis gives compound (P). Compound (P) on treating with 20% H3PO4 at 358 K gives compound (Q). Compound (Q) with Bayer’s reagent gives compound (R). The compound (R) will be 1)2-Methyl propane-1, 2-diol 2)2-Methyl propan-1-ol 3)Butan-2-one 4)2-Methyl propane-1, 3 diol? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev