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The sum of reciprocals of Sharma’s age 3 years ago and 5 years from now is 1/3, then his present age is
  • a)
    7 years
  • b)
    6 years
  • c)
    10 years
  • d)
    8 years
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The sum of reciprocals of Sharma’s age 3 years ago and 5 years f...
let the present age of Sharma’s be x years
3 years ago his age would be-
(x-3)years
5 years from now his age will be -
(x+5)years
according to the problem -
1/(x-3) + 1/(x+5) = 1/3
wen u simplify we get the equation as x^2  - 4x - 21 =0
and we get the roots as -3 and 7..
since age cannot be negative -3 must be rejected.
therefore Sharma’s present age is 7 years.
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Most Upvoted Answer
The sum of reciprocals of Sharma’s age 3 years ago and 5 years f...
Given:
The sum of reciprocals of Sharma's age 3 years ago and 5 years from now is 1/3.

To find:
Sharma's present age.

Solution:

Let's assume Sharma's present age is x years.

Reciprocals:
The reciprocal of a number is obtained by dividing 1 by the number.

So, the reciprocal of Sharma's age 3 years ago would be 1/(x-3) and the reciprocal of Sharma's age 5 years from now would be 1/(x+5).

Equation:
According to the given information, the sum of these reciprocals is equal to 1/3:

1/(x-3) + 1/(x+5) = 1/3

Multiplying through by the common denominator:

3[(x+5) + (x-3)] = (x-3)(x+5)

Simplifying the equation:

3(2x + 2) = x^2 + 2x - 15

6x + 6 = x^2 + 2x - 15

Rearranging the terms:

x^2 - 4x - 21 = 0

Factoring the quadratic equation:

(x - 7)(x + 3) = 0

Setting each factor equal to zero:

x - 7 = 0 or x + 3 = 0

Solving for x:

x = 7 or x = -3

Conclusion:
Since age cannot be negative, Sharma's present age is 7 years (Option A).
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Question Description
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