M²-14m+13=0 solve this quadratic equation?

Question

Answer

Answer

Answer

M²-14m+13 = 0
m²-13m-m+13 = 0
m(m-13)-1(m-13) = 0
(m-1)(m-13) = 0
m = 1 & 13

Answer

Solving Quadratic Equation M²-14m+13=0

Step 1: Identify the coefficients

a = 1 (coefficient of M²)

b = -14 (coefficient of m)

c = 13 (constant term)

Step 2: Apply the quadratic formula

The quadratic formula is given by:

x = (-b ± √(b² - 4ac)) / 2a

Substituting the values of a, b, and c, we get:

m = (14 ± √(14² - 4(1)(13))) / 2(1)

Step 3: Simplify the expression under the square root

14² = 196

4ac = 4(1)(13) = 52

196 - 52 = 144

√144 = 12

Substituting in the formula, we get:

m = (14 ± 12) / 2

Step 4: Solve for m

m = (14 + 12) / 2 = 13

m = (14 - 12) / 2 = 1

Therefore, the solutions are:

m = 13

m = 1

Answer

Answer

M²-14m+13=0
=> m²-13m-m+13=0
=> m(m-13)-1(m-13) = 0
=> (m-1)(m-13)=0
=> m= 1 and 13

Answer

M^2 - 13 m - m + 13 = 0
M ( m - 13 ) - 1 ( m - 13) = 0
( M - 1 ) ( m - 13 ) = 0
M = 1
Or, m - 13 = 0
m = 13

Answer

M2-14m+13=0 m2-13m-m+13=0 m(m-13)-1(m-13)=0 (m-13) (m-1)=0 m=13 &1

Answer

Answer

M^2 -14m+13=0 gives, m^2-m-13m+13=0 m(m-1)-13(m-1)=0 (m-1)(m-13)=0 m-1=0. |. m-13=0 m=1. |. m=13

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