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A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
  • a)
    5
  • b)
    6
  • c)
    5.5
  • d)
    8
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A can finish a work in 18 days and B can do the same work in 15 days. ...
B's 10 day's work = (1/15 * 10) = 2/3
Remaining work = (1 - 2/3) = 1/3.
Now, 1/18 work is done by A in 1 day.
Therefore
 1/3 work is done by A in
(18 * 1/3)= 6 days.
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Most Upvoted Answer
A can finish a work in 18 days and B can do the same work in 15 days. ...
Solution:

Given:
A can finish the work in 18 days.
B can finish the work in 15 days.
B worked for 10 days.

Calculating the work done by B:
One day work of B = 1/15
Work done by B in 10 days = 10*(1/15) = 2/3

Calculating the work remaining:
Remaining work = 1 - 2/3 = 1/3

Calculating the work done by A in a day:
One day work of A = 1/18

Calculating the time taken by A to finish the remaining work:
Let A takes x days to finish the remaining work.
Work done by A in x days = x*(1/18)
According to the question,
Work done by A + Work done by B = Remaining work
x*(1/18) + 2/3 = 1/3
x/18 = 1/3 - 2/3
x/18 = -1/3
x = -6
Since time cannot be negative, we take the positive value.
Therefore, A alone can finish the remaining work in 6 days.
Therefore, the correct answer is option B) 6 days.
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A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?a)5b)6c)5.5d)8Correct answer is option 'B'. Can you explain this answer?
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