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if log 2 = 0.30103, the number of digits in 2128 is
  • a)
    38
  • b)
    39
  • c)
    40
  • d)
    41
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
if log 2 = 0.30103, the number of digits in 2128isa)38b)39c)40d)41Corr...
log(2128) = 128log(2) = 128 × 0.30103 ≈ 38.4

ie, its characteristic = 38

Hence, number of digits in 2128 = 38+1 = 39
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Most Upvoted Answer
if log 2 = 0.30103, the number of digits in 2128isa)38b)39c)40d)41Corr...
To find the number of digits in 2128, we need to find the value of log 2128.

We are given that log 2 = 0.30103. This means that 10^0.30103 = 2.

We can rewrite 2128 as 2^(128).

Taking the logarithm of both sides, we have:
log 2128 = log (2^(128))

Using the logarithmic power rule, this can be rewritten as:
log 2128 = 128 * log 2

Substituting the value of log 2 (0.30103) into the equation, we get:
log 2128 = 128 * 0.30103

Calculating this value, we find:
log 2128 ≈ 38.53344

Since we are interested in the number of digits, we round down this value to the nearest whole number.

Therefore, the number of digits in 2128 is 38.

So, the correct answer is option B) 39.
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Community Answer
if log 2 = 0.30103, the number of digits in 2128isa)38b)39c)40d)41Corr...
To find the number of digits multiply 128 with log2 and then add 1.
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if log 2 = 0.30103, the number of digits in 2128isa)38b)39c)40d)41Correct answer is option 'B'. Can you explain this answer?
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