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A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:
  • a)
    4 days
  • b)
    6 days
  • c)
    8 days
  • d)
    12 days
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A takes twice as much time as B or thrice as much time as C to finish ...
Suppose A, B and C take x,x/2 and x/3 days respectively to finish the work.
Then, (1/x + 2/x + 3/x) = 1/2
= 6/x = 1/2
= x = 12
So, B takes (12/2) = 6 days to finish the work.
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Most Upvoted Answer
A takes twice as much time as B or thrice as much time as C to finish ...
We can assume it as c's work =2 so according to the question b's work will be 3 and a's work will be 6. On taking l.c.m. Of 6,3,2 we get 6. So the efficiency of a=1, b=2 and c=3. Now it's said they work together for 2 days so the equation will be (a+b+c) *2 = b*D substitute the values of a, B, C we will get D=6 days.
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Community Answer
A takes twice as much time as B or thrice as much time as C to finish ...
Given:
- A takes twice as much time as B or thrice as much time as C to finish a piece of work.
- Working together, they can finish the work in 2 days.

To find:
- How long does B take to finish the work alone?

Let's assume that:
- B takes x days to finish the work alone.
- A takes 2x days to finish the work alone.
- C takes (2x)/3 days to finish the work alone.

Since they can finish the work together in 2 days, we can set up the following equation:

1/x + 1/(2x) + 1/((2x)/3) = 1/2

Simplifying the equation:
- Multiplying each term by the least common multiple of the denominators (6x), we get:
6 + 3 + 9 = 3x
18 = 3x
x = 6

Therefore, B takes 6 days to finish the work alone. Hence, the correct answer is option 'B'.
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A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:a)4 daysb)6 daysc)8 daysd)12 daysCorrect answer is option 'B'. Can you explain this answer?
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