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What is the value o f log32 - log43.log54...log1615?
  • a)
    1/2
  • b)
    1/3
  • c)
    2/3
  • d)
    1/4
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
What is the value o f log32 - log43.log54...log1615?a)1/2b)1/3c)2/3d)1...
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What is the value o f log32 - log43.log54...log1615?a)1/2b)1/3c)2/3d)1...
Calculation of log values
- log32 = log(2^5) = 5log2
- log43 = log(3^4) = 4log3
- log54 = log(2^7) = 7log5
- ...
- log1615 = log(15^16) = 16log15

Substitute log values
Substitute the log values into the expression log32 - log43.log54...log1615:
= 5log2 - 4log3 - 7log5 - ... - 16log15

Use logarithmic properties
Apply the logarithmic property log(a) - log(b) = log(a/b):
= log(2^5) - log(3^4) + log(5^7) + ... + log(15^16)
= log(2^5 * 5^7 * ... * 15^16)
= log(2^5 * 3^0 * 4^0 * ... * 15^0)
= log(2^5)
= 5log2

Final answer
Therefore, the value of log32 - log43.log54...log1615 is 5log2, which simplifies to log(2^5) = log(32) = 5log2 = 1/4. Hence, the correct answer is option 'D' (1/4).
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What is the value o f log32 - log43.log54...log1615?a)1/2b)1/3c)2/3d)1/4Correct answer is option 'D'. Can you explain this answer?
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