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A particle starts from rest and moving with constant acceleration covers distance x1 in 3 second. and x2 in 5 second .the ratio x1/x2 is . 5/9 please answer with solution .?
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A particle starts from rest and moving with constant acceleration cove...
Problem: A particle starts from rest and moving with constant acceleration covers distance x1 in 3 second and x2 in 5 second. The ratio x1/x2 is 5/9. Find the acceleration of the particle.
Solution:
Let's assume the initial velocity of the particle is u and its acceleration is a.
Distance covered in 3 seconds:
The distance covered by the particle in the first 3 seconds can be calculated using the formula:
x1 = ut + 1/2 at^2
Since the particle starts from rest, u = 0. So, the above formula reduces to:
x1 = 1/2 at^2
Substituting t = 3, we get:
x1 = 1/2 × a × 3^2
x1 = 4.5a
Distance covered in 5 seconds:
Similarly, the distance covered by the particle in the first 5 seconds can be calculated using the same formula:
x2 = ut + 1/2 at^2
Since the particle starts from rest, u = 0. So, the above formula reduces to:
x2 = 1/2 at^2
Substituting t = 5, we get:
x2 = 1/2 × a × 5^2
x2 = 12.5a
Ratio of x1 and x2:
We are given that x1/x2 = 5/9. Substituting the values of x1 and x2, we get:
4.5a / 12.5a = 5/9
Simplifying the above equation, we get:
a = 5/9 × 12.5/4.5
a = 1.23 m/s^2 (approx.)
Therefore, the acceleration of the particle is 1.23 m/s^2.
Solution:
Let's assume the initial velocity of the particle is u and its acceleration is a.
Distance covered in 3 seconds:
The distance covered by the particle in the first 3 seconds can be calculated using the formula:
x1 = ut + 1/2 at^2
Since the particle starts from rest, u = 0. So, the above formula reduces to:
x1 = 1/2 at^2
Substituting t = 3, we get:
x1 = 1/2 × a × 3^2
x1 = 4.5a
Distance covered in 5 seconds:
Similarly, the distance covered by the particle in the first 5 seconds can be calculated using the same formula:
x2 = ut + 1/2 at^2
Since the particle starts from rest, u = 0. So, the above formula reduces to:
x2 = 1/2 at^2
Substituting t = 5, we get:
x2 = 1/2 × a × 5^2
x2 = 12.5a
Ratio of x1 and x2:
We are given that x1/x2 = 5/9. Substituting the values of x1 and x2, we get:
4.5a / 12.5a = 5/9
Simplifying the above equation, we get:
a = 5/9 × 12.5/4.5
a = 1.23 m/s^2 (approx.)
Therefore, the acceleration of the particle is 1.23 m/s^2.
Community Answer
A particle starts from rest and moving with constant acceleration cove...
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A particle starts from rest and moving with constant acceleration covers distance x1 in 3 second. and x2 in 5 second .the ratio x1/x2 is . 5/9 please answer with solution .?
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A particle starts from rest and moving with constant acceleration covers distance x1 in 3 second. and x2 in 5 second .the ratio x1/x2 is . 5/9 please answer with solution .? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle starts from rest and moving with constant acceleration covers distance x1 in 3 second. and x2 in 5 second .the ratio x1/x2 is . 5/9 please answer with solution .? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle starts from rest and moving with constant acceleration covers distance x1 in 3 second. and x2 in 5 second .the ratio x1/x2 is . 5/9 please answer with solution .?.
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