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x2 - 7x + 12 < | x - 4 |
- a)x < 2
- b)x > 4
- c)2 < x < 4
- d)2 ≤ x ≤ 4
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
x2 - 7x + 12 < | x - 4|a)x < 2 b)x > 4c)2 < x < 4 ...
At x = 0, inequality is not satisfied, option (a) is rejected.
At x = 5, inequality is not satisfied, option (b) is rejected.
At x = 2 inequality is not satisfied.
Options (d) are rejected.
Option (c) is correct.
At x = 2 inequality is not satisfied.
Options (d) are rejected.
Option (c) is correct.
Most Upvoted Answer
x2 - 7x + 12 < | x - 4|a)x < 2 b)x > 4c)2 < x < 4 ...
Solution:
Given expression: x^2 - 7x + 12
We need to find the value of |x - 4| such that the expression becomes zero.
Using factorization method, we can write:
x^2 - 7x + 12 = (x - 3)(x - 4)
So, the expression becomes zero when:
(x - 3)(x - 4) = 0
This gives two possible values of x:
x = 3 or x = 4
Now, we need to find the value of |x - 4| for both these values of x:
When x = 3, |x - 4| = |-1| = 1
When x = 4, |x - 4| = |0| = 0
Therefore, the value of |x - 4| such that the expression becomes zero is 2 or 4.
Option C (2 x 4) is the correct answer.
Given expression: x^2 - 7x + 12
We need to find the value of |x - 4| such that the expression becomes zero.
Using factorization method, we can write:
x^2 - 7x + 12 = (x - 3)(x - 4)
So, the expression becomes zero when:
(x - 3)(x - 4) = 0
This gives two possible values of x:
x = 3 or x = 4
Now, we need to find the value of |x - 4| for both these values of x:
When x = 3, |x - 4| = |-1| = 1
When x = 4, |x - 4| = |0| = 0
Therefore, the value of |x - 4| such that the expression becomes zero is 2 or 4.
Option C (2 x 4) is the correct answer.
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Community Answer
x2 - 7x + 12 < | x - 4|a)x < 2 b)x > 4c)2 < x < 4 ...
Ya if they give modulus you should take both positive and negative,that is +(x-4),-(x-4)
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x2 - 7x + 12 < | x - 4|a)x < 2 b)x > 4c)2 < x < 4 d)2 ≤x ≤ 4Correct answer is option 'C'. Can you explain this answer?
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