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The probability that a non-leap year selected at random will have 53 Mondays is
  • a)
    1/7
  • b)
    7/52
  • c)
    52/365
  • d)
    45/52
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The probability that a non-leap year selected at random will have 53 M...
We know that there are 52 weeks in a year. 

There are 7 days in a week

52 weeks will be  to 7*52 = 364 days. 

The remaining 1 day can be any day among Monday, Tuesday,..., Sunday. 
Sample space has seven days as options.  
So probability of getting 53 Sundays in a non-leap year is 1/7
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Community Answer
The probability that a non-leap year selected at random will have 53 M...
Given: A non-leap year is selected at random.

To find: The probability that the selected year will have 53 Mondays.

Solution:

A year has 365 days (52 weeks and 1 day).

In a non-leap year, February has 28 days.

The number of days in a year that are not in February = 365 - 28 = 337 days.

As 337 is not divisible by 7, there will be 52 complete weeks and 1 day left.

If the year starts on a Monday, there will be 53 Mondays in the year as the extra day will also be a Monday.

If the year starts on any other day, there will be 52 Mondays in the year.

There are 7 possible ways in which a year can start (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday).

Out of these, only one way is favorable for having 53 Mondays (starting on Monday).

Therefore, the required probability = favorable outcomes/total outcomes = 1/7.

Hence, option A is the correct answer.
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The probability that a non-leap year selected at random will have 53 Mondays isa)1/7b)7/52c)52/365d)45/52Correct answer is option 'A'. Can you explain this answer?
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