The probability that a non-leap year selected at random will have 53 M...
We know that there are 52 weeks in a year.
There are 7 days in a week
52 weeks will be to 7*52 = 364 days.
The remaining 1 day can be any day among Monday, Tuesday,..., Sunday.
Sample space has seven days as options.
So probability of getting 53 Sundays in a non-leap year is 1/7
The probability that a non-leap year selected at random will have 53 M...
Given: A non-leap year is selected at random.
To find: The probability that the selected year will have 53 Mondays.
Solution:
A year has 365 days (52 weeks and 1 day).
In a non-leap year, February has 28 days.
The number of days in a year that are not in February = 365 - 28 = 337 days.
As 337 is not divisible by 7, there will be 52 complete weeks and 1 day left.
If the year starts on a Monday, there will be 53 Mondays in the year as the extra day will also be a Monday.
If the year starts on any other day, there will be 52 Mondays in the year.
There are 7 possible ways in which a year can start (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday).
Out of these, only one way is favorable for having 53 Mondays (starting on Monday).
Therefore, the required probability = favorable outcomes/total outcomes = 1/7.
Hence, option A is the correct answer.