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A basket contains 5 black and 8 yellow balls. Four balls are drawn at random and not replaced. What is the probability that they are of different colours alternatively.
  • a)
    56/429
  • b)
    57/429
  • c)
    61/429
  • d)
    68/429
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A basket contains 5 black and 8 yellow balls. Four balls are drawn at ...
sol⇒ BYBY + YBYB = (5/13)*(8/12)*(4/11)*(7/10) + (8/13)*(5/12)*(7/11)*(4/10)
= 56/429
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Most Upvoted Answer
A basket contains 5 black and 8 yellow balls. Four balls are drawn at ...
sol⇒ BYBY + YBYB = (5/13)*(8/12)*(4/11)*(7/10) + (8/13)*(5/12)*(7/11)*(4/10)
= 56/429
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Community Answer
A basket contains 5 black and 8 yellow balls. Four balls are drawn at ...
sol⇒ BYBY + YBYB = (5/13)*(8/12)*(4/11)*(7/10) + (8/13)*(5/12)*(7/11)*(4/10)
= 56/429
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