What will be remainder when 1212121212... 300 times, is being divided ...
This number 1212121212... 300 times is divisible by 9. So, we can write 1212121212...300 times = 9 N, where N is the quotient obtained when divided by 9. Now this question is like -
Now we will have to find the reminder obtained when 134680134680.. . 50 times is divided by 11.
For this, we are supposed to use the divisibility rule of 11 from right hand side. [Using the divisibility rule from left hand side might give us the wrong remainder, like if we find out the remainder obtained when 12 is divided by 11, remainder = 1 = (2-1)≠(1 - 2)]

Alternatively, divisibility rule of 10" - 1, n = 2 can be used to find the remainder in this case.
View all questions of this test
What will be remainder when 1212121212... 300 times, is being divided ...
The answer is 36 option d
9*134680÷9*11. then if 134680 is divided by 11 gives 7, 3 , 10 , 6, 2, 9, 5, 1, 8, 4, 0 and repeated from 7, 3, 10 so on.
I.e every 11 times repeated so upto 99 times 134680 the remainder is 0
100 th time we got 13468 only divided by 11 will give remainder 4 then multiply with the quotient 9 is 36
What will be remainder when 1212121212... 300 times, is being divided ...
Digits 1212 ..... repeated upto 300
means (12) (12)... upto 150 /99
12/99 = remainder we get is 12
so 12 × 150/99
1800/99
remainder= 18