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A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate atomic mass of the metal if n = 3.
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A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate ...
Given:
Current I = 0.55
weight of metal = 0.55g
t = 100 min = 100 x 60 seconds
So,
w/E = It/F
0.55/(x/3) = [0.55 x 100 x 60]/96500
x = 48.5 = atomic mass of metal.
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A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate ...
Calculating the Atomic Mass of the Metal:
- Given data:
- Current = 0.55 A
- Deposit = 0.55 g
- Time = 100 minutes
- n = 3
- The formula to calculate the amount of substance deposited during electrolysis is:
- Deposit = (I * t * M) / (n * F)
- where:
- I = current (A)
- t = time (s)
- M = atomic mass of the metal (g/mol)
- n = number of electrons transferred
- F = Faraday's constant (96485 C/mol)
- Converting time from minutes to seconds:
- 100 minutes = 6000 seconds
- Substituting the given values into the formula:
- 0.55 g = (0.55 A * 6000 s * M) / (3 * 96485 C/mol)
- Solving for M (atomic mass):
- M = (0.55 g * 3 * 96485 C/mol) / (0.55 A * 6000 s)
- M = 318.909 g/mol
Therefore, the atomic mass of the metal is approximately 318.909 g/mol. This calculation is based on the amount of substance deposited during electrolysis, the current, time, number of electrons transferred, and Faraday's constant.
- Given data:
- Current = 0.55 A
- Deposit = 0.55 g
- Time = 100 minutes
- n = 3
- The formula to calculate the amount of substance deposited during electrolysis is:
- Deposit = (I * t * M) / (n * F)
- where:
- I = current (A)
- t = time (s)
- M = atomic mass of the metal (g/mol)
- n = number of electrons transferred
- F = Faraday's constant (96485 C/mol)
- Converting time from minutes to seconds:
- 100 minutes = 6000 seconds
- Substituting the given values into the formula:
- 0.55 g = (0.55 A * 6000 s * M) / (3 * 96485 C/mol)
- Solving for M (atomic mass):
- M = (0.55 g * 3 * 96485 C/mol) / (0.55 A * 6000 s)
- M = 318.909 g/mol
Therefore, the atomic mass of the metal is approximately 318.909 g/mol. This calculation is based on the amount of substance deposited during electrolysis, the current, time, number of electrons transferred, and Faraday's constant.
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A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate atomic mass of the metal if n = 3.
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A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate atomic mass of the metal if n = 3. for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate atomic mass of the metal if n = 3. covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate atomic mass of the metal if n = 3..
A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate atomic mass of the metal if n = 3. for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate atomic mass of the metal if n = 3. covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current of 0.55 deposits 0.55g of a metal in 100 minutes. Calculate atomic mass of the metal if n = 3..
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