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Point A is 7 m west of point B. Point C is 5 m north of point B. A point D on AB 2 m away from point A meets BC at point E with DE = √34 m. Find the distance EC.
- a)3 m
- b)2 m
- c)4 m
- d)Data inadequate
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
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Point A is 7 m west of point B. Point C is 5 m north of point B. A poi...
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Point A is 7 m west of point B. Point C is 5 m north of point B. A poi...
4 m.
To solve this problem, we can start by drawing a diagram:
```
C
|
|
E
|
|
A-------D-------B
2 m
```
From the given information, we know that AB is a horizontal line and AC is a vertical line. We also know that AD = 2 m and DE = 4 m.
To find the length of BE, we can use the Pythagorean theorem. Let x be the distance from D to C:
AC = 5 m
AD = 2 m
DE = 4 m
CD = AC - AD = 5 m - 2 m = 3 m
Using the Pythagorean theorem in triangle CDE, we have:
DE^2 = CD^2 + CE^2
4^2 = 3^2 + CE^2
16 = 9 + CE^2
CE^2 = 7
CE = sqrt(7) ≈ 2.65 m
Now we can use the Pythagorean theorem in triangle ADE to find the length of AE:
AE^2 = AD^2 + DE^2
AE^2 = 2^2 + 4^2
AE^2 = 20
AE = sqrt(20) ≈ 4.47 m
Finally, we can use the fact that AB is 7 m long to find the length of BE:
BE = AB - AE
BE = 7 m - 4.47 m
BE ≈ 2.53 m
Therefore, DE = 4 m and BE ≈ 2.53 m.
To solve this problem, we can start by drawing a diagram:
```
C
|
|
E
|
|
A-------D-------B
2 m
```
From the given information, we know that AB is a horizontal line and AC is a vertical line. We also know that AD = 2 m and DE = 4 m.
To find the length of BE, we can use the Pythagorean theorem. Let x be the distance from D to C:
AC = 5 m
AD = 2 m
DE = 4 m
CD = AC - AD = 5 m - 2 m = 3 m
Using the Pythagorean theorem in triangle CDE, we have:
DE^2 = CD^2 + CE^2
4^2 = 3^2 + CE^2
16 = 9 + CE^2
CE^2 = 7
CE = sqrt(7) ≈ 2.65 m
Now we can use the Pythagorean theorem in triangle ADE to find the length of AE:
AE^2 = AD^2 + DE^2
AE^2 = 2^2 + 4^2
AE^2 = 20
AE = sqrt(20) ≈ 4.47 m
Finally, we can use the fact that AB is 7 m long to find the length of BE:
BE = AB - AE
BE = 7 m - 4.47 m
BE ≈ 2.53 m
Therefore, DE = 4 m and BE ≈ 2.53 m.
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Point A is 7 m west of point B. Point C is 5 m north of point B. A point D on AB 2 m away from point A meets BC at point E with DE = √34 m. Find the distance EC.a)3 mb)2 mc)4 md)Data inadequatee)None of theseCorrect answer is option 'B'. Can you explain this answer?
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Point A is 7 m west of point B. Point C is 5 m north of point B. A point D on AB 2 m away from point A meets BC at point E with DE = √34 m. Find the distance EC.a)3 mb)2 mc)4 md)Data inadequatee)None of theseCorrect answer is option 'B'. Can you explain this answer? for LR 2025 is part of LR preparation. The Question and answers have been prepared according to the LR exam syllabus. Information about Point A is 7 m west of point B. Point C is 5 m north of point B. A point D on AB 2 m away from point A meets BC at point E with DE = √34 m. Find the distance EC.a)3 mb)2 mc)4 md)Data inadequatee)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for LR 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Point A is 7 m west of point B. Point C is 5 m north of point B. A point D on AB 2 m away from point A meets BC at point E with DE = √34 m. Find the distance EC.a)3 mb)2 mc)4 md)Data inadequatee)None of theseCorrect answer is option 'B'. Can you explain this answer?.
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