A coin is tossed 3 times. Find out the number of possible outcomes. a...
For any multiple independent event, there are nm
total possible outcomes, where n is the number of outcomes per event, and m is the number of such events.
So for a coin, discounting the unlikely event of landing on its side, there are two possible outcomes per event, heads or tails. And it is stated that there are 3 such events. So nm=23=8
.
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A coin is tossed 3 times. Find out the number of possible outcomes. a...
Solution:
When a coin is tossed, there are two possible outcomes - either a head or a tail.
So, for one toss, the number of possible outcomes is 2.
For three tosses, we need to find the total number of possible outcomes. We can use the multiplication principle of counting here.
The multiplication principle of counting states that if there are n ways to perform the first task and m ways to perform the second task, then there are n x m ways to perform both tasks.
Using this principle, we can find the number of possible outcomes for three tosses:
- For the first toss, there are 2 possible outcomes.
- For the second toss, there are again 2 possible outcomes.
- For the third toss, there are 2 possible outcomes.
So, using the multiplication principle, the total number of possible outcomes for three tosses is:
2 x 2 x 2 = 8
Therefore, the correct answer is option B - 8.
A coin is tossed 3 times. Find out the number of possible outcomes. a...
8