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For any positive integer n, prove that n3-n is divisible by 6.?
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For any positive integer n, prove that n3-n is divisible by 6.?
N^3 -n n(n^2-1) n(n+1)(n-1) putting the positive odd value of n in (n+1)(n-1) we got that it is divisible by 2 and by putting the similar value of n in whole we get that it is divisible by 3 hence factors of 6 are 2 and 3. it is divisible by 6
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For any positive integer n, prove that n3-n is divisible by 6.?
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