F₂ generation of a cross between two white flowered strains of Sweet P...
Sahi answer B hoga kyonki epistasis sabse pahle summer squash me dekhi thi jiska ratio tha (12:3:1)....... complementary Gene sabse pahle lethyrus odoratus me dekha tha jiska ratio (9:7) h....... supplimentry Gene(recessive epistasis) coat colour in mice me dekha jiska ratio (9:3:4) h
F₂ generation of a cross between two white flowered strains of Sweet P...
Explanation:
Complementary genes are the genes that work together to produce a particular phenotype. In this case, the cross between two white flowered strains of Sweet Pea yields 9 purple flowered plants : 7 white flowered plants in F₂ generation, indicating that there are two genes controlling the flower color in Sweet Pea. These genes are complementary to each other, meaning that both genes must be present in the dominant form to produce the purple flower phenotype.
The two genes controlling flower color in Sweet Pea are denoted by C and P. The dominant form of gene C produces colorless flowers, while the dominant form of gene P produces purple flowers. The recessive form of both genes produces white flowers.
Thus, the cross between two white flowered strains of Sweet Pea can be represented as follows:
Parent 1: ccPP (white flowers)
Parent 2: ccPP (white flowers)
The F₁ generation of this cross will be heterozygous for both genes and will produce purple flowers:
F₁: CcPp (purple flowers)
When the F₁ generation is self-crossed, the F₂ generation will produce the following phenotypic ratio:
9 C_P_ (purple flowers)
3 C_pp (white flowers)
3 ccP_ (white flowers)
1 ccpp (white flowers)
Thus, the ratio of purple to white flowers is 9:7, indicating that the two genes controlling flower color in Sweet Pea are complementary to each other.
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