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Consider S = (1, 2, 3,... 10). In how many ways two numbers from S can be selected so that the sum of the numbers selected is a double digit number?

  • a)
    36

  • b)
    16

  • c)
    29

  • d)
    9C2 - 5C2

Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Consider S = (1, 2, 3,... 10). In how many ways two numbers from S can...
Given, S=(1, 2, 3, …,10).


Two numbers from S are to be selected, such that the sum of the numbers selected is a double-digit number.


If one of the selected number is 10, then, the other number can be any one of 1, 2, 3, ..., 9. So, the number of ways =9.


If one of the selected number is 9, then, the other number can be any one of 1, 2, 3, ..., 8. So, the number of ways =8.


If one of the selected number is 8, then, the other number can be any one of 2, 3, ..., 7. So, the number of ways =6.


If one of the selected number is 7, then, the other number can be any one of 3, 4, ..., 6. So, the number of ways =4.


If one of the selected number is 6, then, the other number can be any one of 4, 5. So, the number of ways =2.


⇒ Total number of ways =9+8+6+4+2=29


Hence, the correct answer is 29.
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Most Upvoted Answer
Consider S = (1, 2, 3,... 10). In how many ways two numbers from S can...
Points to remember for this question:
              
You do not take the same number twice i.e (10,10) (6,6) (7,7)(5,5) are not taken into consideration.

We are selecting two numbers but the order does not matter, so (10,1) and (1,10) give us one count, they are essentially the same.

Now we can make all the possible sets:

let's start backwards:

10 + {1,2,3,4,5,6,7,8,9}   = 9 ways.

9  +{1,2,3,4,5,6,7,8}  = 8 ways.

8 + {2,3,4,5,6,7}  = 6 ways.

7 + {3,4,5,6}  = 4 ways.

6 + {4,5}  = 2 ways

hence  9+8+6+4+2 = 29 ways.


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Community Answer
Consider S = (1, 2, 3,... 10). In how many ways two numbers from S can...
Approach:
To find the number of ways two numbers from S can be selected so that the sum of the numbers selected is a double-digit number, we can follow the below approach:

- Find the total number of ways of selecting two numbers from S.
- Find the number of ways of selecting two numbers from S such that the sum is a single digit number.
- Subtract the number of ways found in step 2 from the total number of ways found in step 1 to get the required number of ways.

Calculation:
Total number of ways of selecting two numbers from S = 10C2 = 45.

Number of ways of selecting two numbers from S such that the sum is a single digit number:

- (1,2), (1,3), (1,4), (1,5), (1,6), (1,7), (1,8), (1,9)
- (2,1), (2,3), (2,4), (2,5), (2,6), (2,7), (2,8)
- (3,1), (3,2), (3,4), (3,5), (3,6)
- (4,1), (4,2), (4,3), (4,5)
- (5,1), (5,2), (5,3), (5,4)
- (6,1), (6,2), (6,3)
- (7,1), (7,2)
- (8,1)
- Total number of ways = 29.

Required number of ways = Total number of ways - Number of ways of selecting two numbers from S such that the sum is a single digit number
= 45 - 29
= 16.

Therefore, the required number of ways two numbers from S can be selected so that the sum of the numbers selected is a double-digit number is 16. Hence, option (c) is the correct answer.
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