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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. What is the actual speed of the car?
- a)30 km/hr
- b)35 km/hr
- c)25 km/hr
- d)40 km/hr
Correct answer is option 'B'. Can you explain this answer?
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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 m...
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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 m...
Given:
The car travels with 5/7 of its actual speed.
The car covers 42 km in 1 hr 40 min 48 sec.
To find:
The actual speed of the car.
Solution:
Let us assume the actual speed of the car as 'x' km/hr.
As per the given condition, the car travels with 5/7 of its actual speed:
Actual speed = 7/5 × (5/7 of actual speed) = 7/5 × x × 5/7 = x km/hr.
We know that,
Distance = Speed × Time
Given, distance covered by the car = 42 km
Time taken by the car = 1 hr 40 min 48 sec = 1 + 40/60 + 48/3600 = 1.68 hours
So, using the above formula, we can write:
42 = x × 1.68
x = 42/1.68
x = 25 km/hr
Therefore, the actual speed of the car is 25 km/hr.
Answer: Option B (25 km/hr)
The car travels with 5/7 of its actual speed.
The car covers 42 km in 1 hr 40 min 48 sec.
To find:
The actual speed of the car.
Solution:
Let us assume the actual speed of the car as 'x' km/hr.
As per the given condition, the car travels with 5/7 of its actual speed:
Actual speed = 7/5 × (5/7 of actual speed) = 7/5 × x × 5/7 = x km/hr.
We know that,
Distance = Speed × Time
Given, distance covered by the car = 42 km
Time taken by the car = 1 hr 40 min 48 sec = 1 + 40/60 + 48/3600 = 1.68 hours
So, using the above formula, we can write:
42 = x × 1.68
x = 42/1.68
x = 25 km/hr
Therefore, the actual speed of the car is 25 km/hr.
Answer: Option B (25 km/hr)
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