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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. What is the actual speed of the car?
  • a)
    30 km/hr
  • b)
    35 km/hr
  • c)
    25 km/hr
  • d)
    40 km/hr
Correct answer is option 'B'. Can you explain this answer?
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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 m...

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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 m...
Given:
The car travels with 5/7 of its actual speed.
The car covers 42 km in 1 hr 40 min 48 sec.

To find:
The actual speed of the car.

Solution:
Let us assume the actual speed of the car as 'x' km/hr.

As per the given condition, the car travels with 5/7 of its actual speed:
Actual speed = 7/5 × (5/7 of actual speed) = 7/5 × x × 5/7 = x km/hr.

We know that,
Distance = Speed × Time
Given, distance covered by the car = 42 km
Time taken by the car = 1 hr 40 min 48 sec = 1 + 40/60 + 48/3600 = 1.68 hours

So, using the above formula, we can write:
42 = x × 1.68
x = 42/1.68
x = 25 km/hr

Therefore, the actual speed of the car is 25 km/hr.

Answer: Option B (25 km/hr)
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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 m...
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A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. What is the actual speed of the car? a)30 km/hrb)35 km/hrc)25 km/hr d)40 km/hrCorrect answer is option 'B'. Can you explain this answer?
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