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How much work done to rotate à magnet of dipole moment m in a magnetic field B through 180 degree? (A)mB/2 (B) 2MB (C)MB (D)3MB/2 answer is B how? (they are not given initial angle)?
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How much work done to rotate à magnet of dipole moment m in a magnetic...
Calculation of Work Done in Rotating a Magnet in a Magnetic Field

Introduction
The work done in rotating a magnet in a magnetic field depends on the dipole moment of the magnet and the strength of the magnetic field. The work done can be calculated using the formula W = -mBcosθ, where W is the work done, m is the dipole moment, B is the magnetic field, and θ is the angle between the direction of the magnetic field and the direction of the dipole moment.

Given
The question does not provide the initial angle between the direction of the magnetic field and the direction of the dipole moment.

Solution
To calculate the work done in rotating a magnet of dipole moment m in a magnetic field B through 180 degrees, we can assume that the initial angle between the direction of the magnetic field and the direction of the dipole moment is 0 degrees.

Using the formula W = -mBcosθ, we can calculate the work done as follows:

W = -mBcos180
W = -mB(-1)
W = mB

Therefore, the work done in rotating a magnet of dipole moment m in a magnetic field B through 180 degrees is equal to 2MB.

Answer
The correct answer is (B) 2MB.
Community Answer
How much work done to rotate à magnet of dipole moment m in a magnetic...
W=MB(cosø1-cosø2)
W=MB(cos0 -cos180)
W=MB[1-(-1)]
W=MB[1+1]
W=2MB
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How much work done to rotate à magnet of dipole moment m in a magnetic field B through 180 degree? (A)mB/2 (B) 2MB (C)MB (D)3MB/2 answer is B how? (they are not given initial angle)?
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