Balloon of mass M is descending with a constant acceleration g/3. when...
Balloon of mass M is descending with a constant acceleration g/3. when...
Given information:
- Mass of the balloon, M
- Acceleration of the balloon, g/3 (descending)
- Mass of the released object, m
- Acceleration of the released object, g/3 (rising)
Analysis:
We can analyze this scenario using Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
Descending balloon:
When the balloon is descending with a constant acceleration of g/3, the net force acting on it is given by the equation F_balloon = M * (g/3). This force is directed downwards due to gravity.
Rising object:
When the mass m is released from the balloon and starts rising with the same acceleration of g/3, the net force acting on it is given by the equation F_object = m * (g/3). This force is directed upwards to counteract the force of gravity.
Equilibrium:
Since the released object is rising with the same acceleration as the descending balloon, the net force on the object must be equal in magnitude and opposite in direction to the net force on the balloon for them to remain in equilibrium.
Therefore, we have F_balloon = F_object.
M * (g/3) = m * (g/3)
Simplification:
Canceling out the common term (g/3) on both sides of the equation, we get:
M = m
Conclusion:
The mass of the released object, m, is equal to the mass of the balloon, M. Therefore, the value of m is equal to M.
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.