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The densities of wood and benzene at zero degree centigrade are 880 kg per metre cube and 900 kg per metre cube respectively. The coefficient of volume expansion of wood is 1.2 *10 to the power -3 and of benzene is 1.5 into 10 to the power -3. The approximate temperature at which a piece of this wood would just sink in Benzene at the same temperature is.?
Most Upvoted Answer
The densities of wood and benzene at zero degree centigrade are 880 kg...
first you should know that
piece of wood "just" sink in benzene means their densities are equal at the time they sink.

then you should know the equation which is derived from the Boyle's law and volume expansion equations (i'm not going to derive it here) i.e.
d' = d / [1+yT]
whre d' : density of the object after the expansion
         d : density of the object 
         y : coefficient of volume expansion of the object
         T : temperature difference 

so, therefore;
d' of wood = d' of benzene  [according to the first fact]
therefore according to the second fact
d[wood] / {1+ (y[wood](t-0) } = d[benzene] / {1+ (y[benzene](t-0) }
i.e.
900/ { 1 + (1.5*10^-3)t } = 880/ { 1 + (1.2*10^-3)t }
t = 1/ (12*10^-3)
t = 83 degrees Celsius 
Community Answer
The densities of wood and benzene at zero degree centigrade are 880 kg...

Calculation of Temperature for Wood to Sink in Benzene

Wood will sink in benzene when the density of wood equals the density of benzene at that temperature. This can be calculated using the principle of volume expansion with temperature.

Formula:
Density = Mass / Volume

Volume Expansion Formula:
ΔV/V = β * ΔT

Calculations:
1. Let the initial volume of wood be V and its density be ρw
2. Let the initial volume of benzene be V and its density be ρb
3. Let the final temperature be T

At initial temperature (T = 0°C):
Density of wood, ρw = 880 kg/m³
Density of benzene, ρb = 900 kg/m³

At final temperature (T = T°C):
Density of wood = 880 kg/m³ / (1 + 1.2 * 10^-3 * T)
Density of benzene = 900 kg/m³ / (1 + 1.5 * 10^-3 * T)

Equating the densities:
880 / (1 + 1.2 * 10^-3 * T) = 900 / (1 + 1.5 * 10^-3 * T)

Solving for T:
T ≈ 158.33°C

Therefore, the approximate temperature at which a piece of wood would just sink in benzene is around 158.33°C. At this temperature, the density of wood will equal the density of benzene, causing it to sink.
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The densities of wood and benzene at zero degree centigrade are 880 kg per metre cube and 900 kg per metre cube respectively. The coefficient of volume expansion of wood is 1.2 *10 to the power -3 and of benzene is 1.5 into 10 to the power -3. The approximate temperature at which a piece of this wood would just sink in Benzene at the same temperature is.?
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The densities of wood and benzene at zero degree centigrade are 880 kg per metre cube and 900 kg per metre cube respectively. The coefficient of volume expansion of wood is 1.2 *10 to the power -3 and of benzene is 1.5 into 10 to the power -3. The approximate temperature at which a piece of this wood would just sink in Benzene at the same temperature is.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The densities of wood and benzene at zero degree centigrade are 880 kg per metre cube and 900 kg per metre cube respectively. The coefficient of volume expansion of wood is 1.2 *10 to the power -3 and of benzene is 1.5 into 10 to the power -3. The approximate temperature at which a piece of this wood would just sink in Benzene at the same temperature is.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The densities of wood and benzene at zero degree centigrade are 880 kg per metre cube and 900 kg per metre cube respectively. The coefficient of volume expansion of wood is 1.2 *10 to the power -3 and of benzene is 1.5 into 10 to the power -3. The approximate temperature at which a piece of this wood would just sink in Benzene at the same temperature is.?.
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