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I. a2 - 2a - 8 = 0,
II. b2 = 9 to solve both the equations to find the values of a and b?
II. b2 = 9 to solve both the equations to find the values of a and b?
- a)If a < b
- b)If a ≤ b
- c)If the relationship between a and b cannot be established
- d)If a > b
- e)If a ≥ b
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
I. a2- 2a - 8 = 0,II. b2= 9 to solve both the equations to find the va...
Explanation:
I. (a - 4)(a + 2) = 0
=> a = 4, -2
II. b2 = 9
=> b = ± 3
-2 < 3, -2 > -3, 4 > 3, 4 > -3,
No relation can be established between a and b.
=> a = 4, -2
II. b2 = 9
=> b = ± 3
-2 < 3, -2 > -3, 4 > 3, 4 > -3,
No relation can be established between a and b.
Most Upvoted Answer
I. a2- 2a - 8 = 0,II. b2= 9 to solve both the equations to find the va...
Explanation:
I. (a - 4)(a + 2) = 0
=> a = 4, -2
II. b2 = 9
=> b = ± 3
-2 < 3, -2 > -3, 4 > 3, 4 > -3,
No relation can be established between a and b.
=> a = 4, -2
II. b2 = 9
=> b = ± 3
-2 < 3, -2 > -3, 4 > 3, 4 > -3,
No relation can be established between a and b.
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Community Answer
I. a2- 2a - 8 = 0,II. b2= 9 to solve both the equations to find the va...
To solve equation I, we can use factoring:
a^2 - 2a - 8 = 0
(a - 4)(a + 2) = 0
Setting each factor equal to zero:
a - 4 = 0 or a + 2 = 0
a = 4 or a = -2
To solve equation II, we can use the square root property:
b^2 = 9
Taking the square root of both sides:
b = ±√9
b = ±3
So the solutions for the equations are:
a = 4 or a = -2
b = 3 or b = -3
a^2 - 2a - 8 = 0
(a - 4)(a + 2) = 0
Setting each factor equal to zero:
a - 4 = 0 or a + 2 = 0
a = 4 or a = -2
To solve equation II, we can use the square root property:
b^2 = 9
Taking the square root of both sides:
b = ±√9
b = ±3
So the solutions for the equations are:
a = 4 or a = -2
b = 3 or b = -3
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I. a2- 2a - 8 = 0,II. b2= 9 to solve both the equations to find the values of a and b?a)If a < bb)If a ≤ bc)If the relationship between a and b cannot be establishedd)If a > be)If a ≥ bCorrect answer is option 'C'. Can you explain this answer?
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