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A person has near point of his vision shifted to 50 cm. What lens must be used to see an object placed at 25 cm from the eye? What is the power of the lens?
  • a)
    A diverging lens of focal length 50 cm and power – 2 D
  • b)
    A converging lens of focal length 50 cm and power + 2 D
  • c)
    A converging lens of focal lens 50 cm and power – 2 D
  • d)
    A diverging lens of focal length 50 cm and power + 2 D
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A person has near point of his vision shifted to 50 cm. What lens must...
A person suffering from hypermetropia can see distinct objects clearly but faces difficulty in seeing nearby objects clearly. It happens because the eye lens focuses the incoming divergent rays beyond the retina. This defect of vision is corrected by using a convex lens. A convex lens of suitable power converges the incoming light.

The given person will be able to clearly see the object kept at 25 cm (near point of the normal eye), if the image of the object is formed at his near point, which is given as 1 m.

Object distance, u = -25 cm

Image distance, v = -50cm

Focal length, f

Using the lens formula,

1/f = 1/v - 1/u

here u = -25 cm

v = -50cm

substituting & calculating for f, we get

f = +50cm = +0.5 m

Power P = 1/f = +2 D
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Most Upvoted Answer
A person has near point of his vision shifted to 50 cm. What lens must...
Explanation:

Given Data:
Near point of vision = 50 cm
Distance of object from eye = 25 cm

Calculation:
To see an object placed at 25 cm from the eye, the lens must provide the required additional power to bring the image to the near point of vision.

Additional Power Required:
Additional Power = 1 / (required focal length) - 1 / (current focal length)
Additional Power = 1 / (-0.25) - 1 / (-0.50)
Additional Power = -4 + 2 = -2 D

Therefore, a converging lens of focal length 50 cm and power +2 D must be used to see an object placed at 25 cm from the eye.
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Community Answer
A person has near point of his vision shifted to 50 cm. What lens must...
When object is placed at 25 cm, then a virtual image should form at 50 cm. 
So, u = -25 cm, v= -50 cm. 
So, 1/f = 1/-50 - 1/-25 
f = 50 cm = 0.5 m 
Power, P = 1/f = 1/0.5 =  +2D 
Therefore , a convex lens is needed.
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A person has near point of his vision shifted to 50 cm. What lens must be used to see an object placed at 25 cm from the eye? What is the power of the lens?a)A diverging lens of focal length 50 cm and power – 2 Db)A converging lens of focal length 50 cm and power + 2 Dc)A converging lens of focal lens 50 cm and power – 2 Dd)A diverging lens of focal length 50 cm and power + 2 DCorrect answer is option 'B'. Can you explain this answer?
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A person has near point of his vision shifted to 50 cm. What lens must be used to see an object placed at 25 cm from the eye? What is the power of the lens?a)A diverging lens of focal length 50 cm and power – 2 Db)A converging lens of focal length 50 cm and power + 2 Dc)A converging lens of focal lens 50 cm and power – 2 Dd)A diverging lens of focal length 50 cm and power + 2 DCorrect answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A person has near point of his vision shifted to 50 cm. What lens must be used to see an object placed at 25 cm from the eye? What is the power of the lens?a)A diverging lens of focal length 50 cm and power – 2 Db)A converging lens of focal length 50 cm and power + 2 Dc)A converging lens of focal lens 50 cm and power – 2 Dd)A diverging lens of focal length 50 cm and power + 2 DCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person has near point of his vision shifted to 50 cm. What lens must be used to see an object placed at 25 cm from the eye? What is the power of the lens?a)A diverging lens of focal length 50 cm and power – 2 Db)A converging lens of focal length 50 cm and power + 2 Dc)A converging lens of focal lens 50 cm and power – 2 Dd)A diverging lens of focal length 50 cm and power + 2 DCorrect answer is option 'B'. Can you explain this answer?.
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