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Prove that the diagonals of a rectangle are equal and bisect each other using COORDINATE GEOMETRY.?
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Proof that the Diagonals of a Rectangle are Equal and Bisect Each Other using Coordinate Geometry





Given:
- Let the coordinates of the vertices of the rectangle be A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4).
- Assume the rectangle is placed in such a way that sides AB and CD are parallel to the x-axis and sides AD and BC are parallel to the y-axis.

Proof:



  • Step 1: Calculate the Midpoints of the Diagonals

  • - The midpoint of diagonal AC is M(xm, ym) where xm = (x1 + x3) / 2 and ym = (y1 + y3) / 2.
    - The midpoint of diagonal BD is N(xn, yn) where xn = (x2 + x4) / 2 and yn = (y2 + y4) / 2.

  • Step 2: Show that the Midpoints are Equal

  • - To prove that the diagonals bisect each other, we need to show that M is equal to N.
    - Since a rectangle is symmetric about its diagonals, the midpoints of the diagonals are equal.

  • Step 3: Calculate the Length of the Diagonals

  • - The length of diagonal AC is given by sqrt[(x3 - x1)^2 + (y3 - y1)^2].
    - The length of diagonal BD is given by sqrt[(x4 - x2)^2 + (y4 - y2)^2].

  • Step 4: Show that the Lengths of the Diagonals are Equal

  • - Calculate the lengths of the diagonals AC and BD using the coordinates of the vertices.
    - If the lengths of the diagonals are equal, then the diagonals are equal.

    Conclusion:

    - Therefore, we have proved that the diagonals of a rectangle are equal and bisect each other using coordinate geometry.




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