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The average age of a man and his two sons, born on the same day, is 30 yr. The ratio of the ages of father to one of the sons is 5 : 2. What is the father’s age.
  • a)
    50 yr                        
  • b)
    30 yr            
  • c)
    45 yr
  • d)
    20 yr                        
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The average age of a man and his two sons, born on the same day, is 30...
According to the question, average age of man and his twin sons = 30

Total age = 30 x 3 = 90 yr

According to the question, Ratio of father and one son = 5 : 2

Ratio of father and both the sons = 5 : 2 : 2(As sons are born on the same day)

5x + 2x +2x = 90 or 9x = 90

X = 10

Age of father = 5 X 10 = 50 yr.
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Most Upvoted Answer
The average age of a man and his two sons, born on the same day, is 30...
Given:
- The average age of a man and his two sons, born on the same day, is 30 yr.
- The ratio of the ages of father to one of the sons is 5 : 2.

To find: The father's age.

Solution:
Let the age of the father be 5x and the age of one of the sons be 2x.
The age of the other son will also be 2x, as they were born on the same day.

As per the given condition, the average age of the man and his two sons is 30 years.
Therefore, (5x + 2x + 2x)/3 = 30
Simplifying this, we get:
9x/3 = 30
3x = 30
x = 10

So, the age of the father = 5x = 5*10 = 50 years.

Therefore, the correct option is (a) 50 years.
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