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Points P, Q and R lie on sides BC, CA and AB respectively of triangle ABC such that PQ||AB and QR||BC, prove that RP||CA.?
Most Upvoted Answer
Points P, Q and R lie on sides BC, CA and AB respectively of triangle ...
Proof:

Given: Triangle ABC with points P, Q and R on sides BC, CA and AB respectively such that PQ||AB and QR||BC.

To prove: RP||CA.

Proof:

Step 1: Draw a diagram of the given triangle ABC with points P, Q and R on sides BC, CA and AB respectively such that PQ||AB and QR||BC.

Step 2: Draw a line segment from point R to point C.

Step 3: Since PQ||AB and QR||BC, we have ∠QRC = ∠ABC and ∠PQR = ∠BAC (corresponding angles).

Step 4: Also, since RP is a transversal cutting parallel lines BC and PQ, we have ∠RPA = ∠PQC (alternate angles).

Step 5: Adding ∠QRC and ∠RPA, we get:

∠QRC + ∠RPA = ∠ABC + ∠PQC (using corresponding angles)

Step 6: Simplifying the above equation, we get:

∠QRP = ∠ACB

Step 7: Since ∠QRP and ∠ACB are alternate interior angles, we have RP||CA.

Step 8: Therefore, RP||CA is proved.

Conclusion: Hence, it is proved that RP||CA in the given triangle ABC with points P, Q and R on sides BC, CA and AB respectively such that PQ||AB and QR||BC.
Community Answer
Points P, Q and R lie on sides BC, CA and AB respectively of triangle ...
In triangle ABC PQ||AB =)AQ/QC=CP/PB----(1)(BPT) now QR||BC=) AR/RB=AQ/QC-----(2)(BPT) from(1) and(2) we get AR/RB=CP/PB=) RP||CA(converse of BPT)[proved]
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Points P, Q and R lie on sides BC, CA and AB respectively of triangle ABC such that PQ||AB and QR||BC, prove that RP||CA.?
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