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A particle is thrown up vertically with a speed v1 in air it takes time t1 in upward journey and t2 in downward journey and returns to the starting point with a speed v2 if t2&greater t1 then v1greater v2 how?
Most Upvoted Answer
A particle is thrown up vertically with a speed v1 in air it takes tim...
The time taken for the upward journey, t1, can be calculated using the equation of motion:
v1 = u + at
Since the particle is thrown up vertically, the initial velocity (u) is v1 and the acceleration (a) is -g (negative because it acts in the opposite direction to the motion). Thus, the equation becomes:
0 = v1 - gt1
Solving for t1 gives:
t1 = v1/g
Similarly, for the downward journey, the time taken, t2, can be calculated using the equation of motion:
v2 = u + at
Since the particle is returning to the starting point, the final velocity (v2) is zero. The initial velocity (u) is v2 and the acceleration (a) is g (positive this time because it acts in the same direction as the motion). Thus, the equation becomes:
0 = v2 + gt2
Solving for t2 gives:
t2 = -v2/g
Since the particle returns to the starting point, the total time taken for the entire journey is t1 + t2. Substituting the values of t1 and t2:
Total time = t1 + t2 = v1/g - v2/g = (v1 - v2)/g
v1 = u + at
Since the particle is thrown up vertically, the initial velocity (u) is v1 and the acceleration (a) is -g (negative because it acts in the opposite direction to the motion). Thus, the equation becomes:
0 = v1 - gt1
Solving for t1 gives:
t1 = v1/g
Similarly, for the downward journey, the time taken, t2, can be calculated using the equation of motion:
v2 = u + at
Since the particle is returning to the starting point, the final velocity (v2) is zero. The initial velocity (u) is v2 and the acceleration (a) is g (positive this time because it acts in the same direction as the motion). Thus, the equation becomes:
0 = v2 + gt2
Solving for t2 gives:
t2 = -v2/g
Since the particle returns to the starting point, the total time taken for the entire journey is t1 + t2. Substituting the values of t1 and t2:
Total time = t1 + t2 = v1/g - v2/g = (v1 - v2)/g
Community Answer
A particle is thrown up vertically with a speed v1 in air it takes tim...
Bcoz for free fall v=1/2 gt2
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A particle is thrown up vertically with a speed v1 in air it takes time t1 in upward journey and t2 in downward journey and returns to the starting point with a speed v2 if t2&greater t1 then v1greater v2 how?
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A particle is thrown up vertically with a speed v1 in air it takes time t1 in upward journey and t2 in downward journey and returns to the starting point with a speed v2 if t2&greater t1 then v1greater v2 how? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle is thrown up vertically with a speed v1 in air it takes time t1 in upward journey and t2 in downward journey and returns to the starting point with a speed v2 if t2&greater t1 then v1greater v2 how? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is thrown up vertically with a speed v1 in air it takes time t1 in upward journey and t2 in downward journey and returns to the starting point with a speed v2 if t2&greater t1 then v1greater v2 how?.
A particle is thrown up vertically with a speed v1 in air it takes time t1 in upward journey and t2 in downward journey and returns to the starting point with a speed v2 if t2&greater t1 then v1greater v2 how? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle is thrown up vertically with a speed v1 in air it takes time t1 in upward journey and t2 in downward journey and returns to the starting point with a speed v2 if t2&greater t1 then v1greater v2 how? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is thrown up vertically with a speed v1 in air it takes time t1 in upward journey and t2 in downward journey and returns to the starting point with a speed v2 if t2&greater t1 then v1greater v2 how?.
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