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The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
- a)4.37%
- b)5%
- c)6%
- d)8.75%
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The population of a town increased from 1,75,000 to 2,62,500 in a deca...
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Most Upvoted Answer
The population of a town increased from 1,75,000 to 2,62,500 in a deca...
262500-175000 = 87500
So, increased percentage
= 87500×100/175000 =50%
Average % increase per year = 50/10 = 5% Ans.
So, increased percentage
= 87500×100/175000 =50%
Average % increase per year = 50/10 = 5% Ans.
Community Answer
The population of a town increased from 1,75,000 to 2,62,500 in a deca...
Given: 30% of a% of b = 25% of b% of c
To find: c in terms of a
Solution:
Step 1: Write the given expression in terms of variables
30% of a% of b = 0.3a/100 * b
25% of b% of c = 0.25b/100 * c
Step 2: Equate the two expressions and simplify
0.3a/100 * b = 0.25b/100 * c
0.3a * b = 0.25b * c
c = (0.3a * b) / (0.25b)
c = 1.2a
Step 3: Compare the expression obtained with the given options
The correct option is B) 1.20a
Therefore, the value of c is 1.20a.
To find: c in terms of a
Solution:
Step 1: Write the given expression in terms of variables
30% of a% of b = 0.3a/100 * b
25% of b% of c = 0.25b/100 * c
Step 2: Equate the two expressions and simplify
0.3a/100 * b = 0.25b/100 * c
0.3a * b = 0.25b * c
c = (0.3a * b) / (0.25b)
c = 1.2a
Step 3: Compare the expression obtained with the given options
The correct option is B) 1.20a
Therefore, the value of c is 1.20a.
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The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:a)4.37%b)5%c)6% d)8.75%Correct answer is option 'B'. Can you explain this answer?
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