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Two riders on the horseback with a gun and a bullet proof shield were moving towards each other at a constant speed of 20 km/h and 5 km/h respectively. When they were 100 km apart, they started firing bullets at each other at the speed of 10 km/h. When a bullet of rider 1 hits the shield of rider 2, rider 2 fires a bullet and the process continues vice versa. Neglecting the time lag at the instant when the bullet hits the shield and the rider fires the shot, find the total distance covered by all the bullets shot by both the riders.
- a)50 km
- b)40 km
- c)25 km
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Two riders on the horseback with a gun and a bullet proof shield were ...
This question has actually got nothing to do with bullets initially. We can see that it takes them 4 hours to reach each other. And this is the same time for which bullets will cover some distance.
So, the total distance covered by the bullet = 4 x 1 0 = 40 km
So, the total distance covered by the bullet = 4 x 1 0 = 40 km
Most Upvoted Answer
Two riders on the horseback with a gun and a bullet proof shield were ...
Bullet from rider 1 takes 100/15 = 6.6 hrs to meet rider 2. But rider 1 is faster than the bullet. so only the butter fired by rider 1 is taken into account. They both meet in 4 hrs, So distance = 4hrs * 10 = 40 km
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Two riders on the horseback with a gun and a bullet proof shield were ...
**Given information:**
- Rider 1's speed = 20 km/h
- Rider 2's speed = 5 km/h
- Distance between the riders = 100 km
- Bullet speed = 10 km/h
**Calculating the time taken for the riders to meet:**
Let's assume the time taken for the riders to meet is t hours.
- Distance covered by Rider 1 in t hours = 20t km
- Distance covered by Rider 2 in t hours = 5t km
Since they are moving towards each other, the sum of their distances covered should be equal to the distance between them:
20t + 5t = 100
25t = 100
t = 4 hours
So, it takes 4 hours for the riders to meet.
**Calculating the distance covered by the bullets:**
During these 4 hours, both riders will keep firing bullets at each other.
- Distance covered by Rider 1's bullets = 10 km/h x 4 hours = 40 km
- Distance covered by Rider 2's bullets = 10 km/h x 4 hours = 40 km
Therefore, the total distance covered by all the bullets shot by both riders is 40 km. Hence, option B is the correct answer.
- Rider 1's speed = 20 km/h
- Rider 2's speed = 5 km/h
- Distance between the riders = 100 km
- Bullet speed = 10 km/h
**Calculating the time taken for the riders to meet:**
Let's assume the time taken for the riders to meet is t hours.
- Distance covered by Rider 1 in t hours = 20t km
- Distance covered by Rider 2 in t hours = 5t km
Since they are moving towards each other, the sum of their distances covered should be equal to the distance between them:
20t + 5t = 100
25t = 100
t = 4 hours
So, it takes 4 hours for the riders to meet.
**Calculating the distance covered by the bullets:**
During these 4 hours, both riders will keep firing bullets at each other.
- Distance covered by Rider 1's bullets = 10 km/h x 4 hours = 40 km
- Distance covered by Rider 2's bullets = 10 km/h x 4 hours = 40 km
Therefore, the total distance covered by all the bullets shot by both riders is 40 km. Hence, option B is the correct answer.
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Two riders on the horseback with a gun and a bullet proof shield were moving towards each other at a constant speed of 20 km/h and 5 km/h respectively. When they were 100 km apart, they started firing bullets at each other at the speed of 10 km/h. When a bullet of rider 1 hits the shield of rider 2, rider 2 fires a bullet and the process continues vice versa. Neglecting the time lag at the instant when the bullet hits the shield and the rider fires the shot, find the total distance covered by all the bullets shot by both the riders.a)50 kmb)40 kmc)25 kmd)None of theseCorrect answer is option 'B'. Can you explain this answer?
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