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If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:

  • a)
    2.870

  • b)
    2.967

  • c)
    3.876

  • d)
    3.912

Correct answer is option 'C'. Can you explain this answer?
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If log 2 = 0.3010 and log 3 = 0.4771, the value of log5512 is:a)2.870b...
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If log 2 = 0.3010 and log 3 = 0.4771, the value of log5512 is:a)2.870b...
Calculating log5512 using the given values of log 2 and log 3.

Given: log 2 = 0.3010 and log 3 = 0.4771

To find: log5512

We can write 5512 as a product of powers of 2 and 3:

5512 = 27 × 33

Taking the logarithm of both sides:

log 5512 = log (27 × 33)

Using the properties of logarithms:

log 5512 = log 27 + log 33

Substituting the given values of log 2 and log 3:

log 5512 = log (23 × 33) + log 3

log 5512 = 3 log 2 + log 3

log 5512 = 3(0.3010) + 0.4771

log 5512 = 0.9030 + 0.4771

log 5512 = 1.3801

Therefore, the value of log5512 is 1.3801.

However, none of the given options match this value. It is possible that there is a mistake in the question or in the answer options.
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If log 2 = 0.3010 and log 3 = 0.4771, the value of log5512 is:a)2.870b)2.967c)3.876d)3.912Correct answer is option 'C'. Can you explain this answer?
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