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When a conductance cell was filled with a 0.0025 M solution of K2SO4, its resistance was 326 Ω. If cell constant is 0.2281 cm-1, the specific conductance (Ω-1cm-1) of K2SO4 solution is:
  • a)
    4.997 × 10-4
  • b)
    5.997 × 10-4
  • c)
    6.997 × 10-4
  • d)
    7.997 × 10-4
Correct answer is option 'C'. Can you explain this answer?
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When a conductance cell was filled with a 0.0025 M solution of K2SO4, ...
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When a conductance cell was filled with a 0.0025 M solution of K2SO4, ...
Conductance =Cell constant *Resistance
i. e    to find conductance 
                  conductance =0.2281*326
                                          =74.3606
          Now in order to find specific conductance 
              use... conductivity =K*1000/molarity 
                      K=conductivity *molarity /1000
                     thereby you find the answer
     Hope it helps you..!!! 66
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Community Answer
When a conductance cell was filled with a 0.0025 M solution of K2SO4, ...
Put the formula resistance =specific resistance *cell constant
Resistance and cell contact is given. Now we can find specific resistance easily. Then inverse d specific resistance that we got from d abv method.. We ll get the ans n the ans ll be 6.99 which is option c
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When a conductance cell was filled with a 0.0025 M solution of K2SO4, its resistance was 326 Ω. If cell constant is 0.2281 cm-1, the specific conductance (Ω-1cm-1) of K2SO4 solution is:a)4.997 × 10-4b)5.997 × 10-4c)6.997 × 10-4d)7.997 × 10-4Correct answer is option 'C'. Can you explain this answer?
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When a conductance cell was filled with a 0.0025 M solution of K2SO4, its resistance was 326 Ω. If cell constant is 0.2281 cm-1, the specific conductance (Ω-1cm-1) of K2SO4 solution is:a)4.997 × 10-4b)5.997 × 10-4c)6.997 × 10-4d)7.997 × 10-4Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about When a conductance cell was filled with a 0.0025 M solution of K2SO4, its resistance was 326 Ω. If cell constant is 0.2281 cm-1, the specific conductance (Ω-1cm-1) of K2SO4 solution is:a)4.997 × 10-4b)5.997 × 10-4c)6.997 × 10-4d)7.997 × 10-4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a conductance cell was filled with a 0.0025 M solution of K2SO4, its resistance was 326 Ω. If cell constant is 0.2281 cm-1, the specific conductance (Ω-1cm-1) of K2SO4 solution is:a)4.997 × 10-4b)5.997 × 10-4c)6.997 × 10-4d)7.997 × 10-4Correct answer is option 'C'. Can you explain this answer?.
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