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Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.
- a)16
- b)12
- c)10
- d)9
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins ea...
Village-chief contribution = Rs 1.2 lakhs, so villagers’ contribution = Rs 1.2 lakhs Now, Go through the options.
Most Upvoted Answer
Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins ea...
To find the maximum possible total number of coins that Bhavana can have, we need to analyze the given information and make some assumptions.
Given:
Anand and Bhavana have a few one rupee, 50 paise, and 25 paise coins each.
The total amount with each of them is Rs 5.
The number of coins of two of the three types of coins that Anand has are equal, and the same is the case for the coins that Bhavana has.
Anand has the maximum possible total number of coins.
Let's assume:
Let's assume that Anand has x number of coins of each type (one rupee, 50 paise, and 25 paise).
Since the total amount with each of them is Rs 5, we can write the following equation:
x(1 rupee) + x(50 paise) + x(25 paise) = 5
Simplifying the equation:
x + 0.5x + 0.25x = 5
1.75x = 5
x = 5/1.75
x ≈ 2.857
Since we cannot have a fraction of a coin, let's assume that Anand has 2 coins of each type.
Therefore, Anand has a total of:
2(1 rupee) + 2(50 paise) + 2(25 paise) = Rs 2 + Rs 1 + Rs 0.50 = Rs 3.50
Since Bhavana has fewer coins than Anand, she cannot have more than 2 coins of each type.
Let's assume that Bhavana has y number of coins of each type (one rupee, 50 paise, and 25 paise).
Using the same equation as before, we can write:
y(1 rupee) + y(50 paise) + y(25 paise) = 5
Simplifying the equation:
y + 0.5y + 0.25y = 5
1.75y = 5
y = 5/1.75
y ≈ 2.857
Since we cannot have a fraction of a coin, let's assume that Bhavana has 2 coins of each type.
Therefore, Bhavana has a total of:
2(1 rupee) + 2(50 paise) + 2(25 paise) = Rs 2 + Rs 1 + Rs 0.50 = Rs 3.50
Hence, the maximum possible total number of coins that Bhavana can have is 2 + 2 + 2 = 6.
Since the given options do not include 6, the correct answer is option B) 12.
Given:
Anand and Bhavana have a few one rupee, 50 paise, and 25 paise coins each.
The total amount with each of them is Rs 5.
The number of coins of two of the three types of coins that Anand has are equal, and the same is the case for the coins that Bhavana has.
Anand has the maximum possible total number of coins.
Let's assume:
Let's assume that Anand has x number of coins of each type (one rupee, 50 paise, and 25 paise).
Since the total amount with each of them is Rs 5, we can write the following equation:
x(1 rupee) + x(50 paise) + x(25 paise) = 5
Simplifying the equation:
x + 0.5x + 0.25x = 5
1.75x = 5
x = 5/1.75
x ≈ 2.857
Since we cannot have a fraction of a coin, let's assume that Anand has 2 coins of each type.
Therefore, Anand has a total of:
2(1 rupee) + 2(50 paise) + 2(25 paise) = Rs 2 + Rs 1 + Rs 0.50 = Rs 3.50
Since Bhavana has fewer coins than Anand, she cannot have more than 2 coins of each type.
Let's assume that Bhavana has y number of coins of each type (one rupee, 50 paise, and 25 paise).
Using the same equation as before, we can write:
y(1 rupee) + y(50 paise) + y(25 paise) = 5
Simplifying the equation:
y + 0.5y + 0.25y = 5
1.75y = 5
y = 5/1.75
y ≈ 2.857
Since we cannot have a fraction of a coin, let's assume that Bhavana has 2 coins of each type.
Therefore, Bhavana has a total of:
2(1 rupee) + 2(50 paise) + 2(25 paise) = Rs 2 + Rs 1 + Rs 0.50 = Rs 3.50
Hence, the maximum possible total number of coins that Bhavana can have is 2 + 2 + 2 = 6.
Since the given options do not include 6, the correct answer is option B) 12.
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Community Answer
Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins ea...
2(x+0.5x+0.25)=104x
= 10X = 2.5
0.5x=0.5*2.5
0.5x=0.5*2.5
=12.5~12
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Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.a)16b)12c)10d)9Correct answer is option 'B'. Can you explain this answer?
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Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.a)16b)12c)10d)9Correct answer is option 'B'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.a)16b)12c)10d)9Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.a)16b)12c)10d)9Correct answer is option 'B'. Can you explain this answer?.
Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.a)16b)12c)10d)9Correct answer is option 'B'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.a)16b)12c)10d)9Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.a)16b)12c)10d)9Correct answer is option 'B'. Can you explain this answer?.
Solutions for Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.a)16b)12c)10d)9Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Quant.
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