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In Mathematics exam, a student scored 30% marks in the first paper, out of the total of 180. How much should he score in second paper out of a total of 150, if he is to get an overall average of at least 50%
  • a)
    74%
  • b)
    76%
  • c)
    70%
  • d)
    80%
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In Mathematics exam, a student scored 30% marks in the first paper, ou...
∵ 30% of 180 + N% of 150 = 50% of (180 + 150) 
⇒ 54 + (N x 150)/100 = 165 
⇒ 3N/2 = 111 
∴ N = (111 x 2) / 3 =74
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Most Upvoted Answer
In Mathematics exam, a student scored 30% marks in the first paper, ou...
Firstly, marks he scored in first paper out of 180 will be
180 x 30÷100 = 54 marks
So he scored 54 marks out of 180 in the first paper.
Now total marks of the examination is 330 i.e 150+180.
50% of 330 is 165.
So in second paper he has to score 165–54=111 marks to get 50% marks over all.
Now the ans is asked in terms of percent so,
111÷150 x 100 = 74%
So he has to get 74 % in the second paper to get a overall percent of 50%.
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Community Answer
In Mathematics exam, a student scored 30% marks in the first paper, ou...
Given:
First paper marks = 30% of 180 = 54
Total marks required for an overall average of at least 50% = (180 + 150) * 50% = 165

To find:
Marks required in the second paper

Solution:
Let x be the marks required in the second paper.

Step 1: Find the total marks obtained by the student in both papers
Total marks obtained = 54 + x

Step 2: Find the percentage of marks obtained by the student out of the total marks
Percentage marks obtained = (Total marks obtained / Total marks) * 100

Step 3: Set up an equation for the given condition of an overall average of at least 50%
(Percentage marks obtained / 2) >= 50%

Step 4: Substitute the values and simplify
((54 + x) / (180 + 150)) * 100 >= 50%
(54 + x) / 330 >= 0.5
54 + x >= 165
x >= 111

Step 5: Round off the answer to the nearest integer
x = 74%

Therefore, the student should score at least 74% marks in the second paper to get an overall average of at least 50%.
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