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A locomotive begins to move with uniform acceleration at the moment when a boy runs past it with a uniform velocity of 2m/s .the velocity of the locomotive when it overtakes the boy is? the answer is 4 how?
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A locomotive begins to move with uniform acceleration at the moment wh...
Explanation: Velocity of Locomotive Overtaking the Boy


Let's assume that:


  • The initial velocity of the locomotive is 0 m/s

  • The uniform acceleration of the locomotive is a

  • The velocity of the boy is constant at 2 m/s

  • The time taken by the locomotive to overtake the boy is t seconds

  • The distance covered by the locomotive during this time is d meters



Calculating the Distance Covered by the Locomotive

The distance covered by the locomotive is given by:

d = 1/2 * a * t^2


Calculating the Final Velocity of the Locomotive

The final velocity of the locomotive is given by:

v = u + a * t

where u is the initial velocity of the locomotive, which is 0 m/s

Substituting the value of t from the first equation in the second equation, we get:

v = u + 2a * d/a

v = 2d/t


Substituting Values and Solving

Now we can substitute the values given in the problem statement:

d = 2t^2

v = 2d/t = 4t

Therefore, the velocity of the locomotive when it overtakes the boy is 4 m/s.
Community Answer
A locomotive begins to move with uniform acceleration at the moment wh...
Distance (s) =boy's velocity (v) ×time ( t )=2t . s(locomotive ) = ut + 1/2 at2 =2 t or ,0 + 1/2at2 = 2t or, at =4 . locomotive's velocity = u+ at = 0 + 4 = 4m/s
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A locomotive begins to move with uniform acceleration at the moment when a boy runs past it with a uniform velocity of 2m/s .the velocity of the locomotive when it overtakes the boy is? the answer is 4 how?
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