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Two identical charges repel each other with a force equal to 1 MG weight when they are 0. 6 m apart in air (g=10m/s^) the value of each charges is?
Most Upvoted Answer
Two identical charges repel each other with a force equal to 1 MG weig...
Given Data:
- Force of repulsion (F) = 1 MG weight = 1 x 10^6 N
- Distance between charges (r) = 0.6 m
- Acceleration due to gravity (g) = 10 m/s^2

Step 1: Calculate the Force between Charges
The force between two charges can be calculated using Coulomb's Law:
F = k * (q1 * q2) / r^2
where:
- F is the force between the charges
- k is the Coulomb constant (8.99 x 10^9 N m^2/C^2)
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges

Step 2: Calculate the Magnitude of Charges
Given that the force of repulsion is 1 MG weight when the charges are 0.6 m apart, we can rearrange Coulomb's Law to solve for the magnitude of the charges:
q1 * q2 = F * r^2 / k
q1 = q2 = sqrt(F * r^2 / k)

Step 3: Substitute Values and Calculate
- Plugging in the given values:
q1 = q2 = sqrt(1 x 10^6 * (0.6)^2 / 8.99 x 10^9)
q1 = q2 = sqrt(0.36 x 10^6 / 8.99)
q1 = q2 = sqrt(40.044)
q1 = q2 ≈ 6.33 x 10^-6 C

Conclusion:
Therefore, the value of each charge is approximately 6.33 x 10^-6 C.
Community Answer
Two identical charges repel each other with a force equal to 1 MG weig...
0.02 micro coulomb
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Two identical charges repel each other with a force equal to 1 MG weight when they are 0. 6 m apart in air (g=10m/s^) the value of each charges is?
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