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A uniform ring of mass M & radius R is placed directly above a uniform sphere of mass 8M & radius R. The centre of ring is at a distance of d=√3R from the centre of the sphere. The gravitational attraction between the sphere and ring is
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A uniform ring of mass M & radius R is placed directly above a uniform...
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A uniform ring of mass M & radius R is placed directly above a uniform...
The gravitational attraction between the sphere and ring is;F=8GM^2÷3R^2...!!
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A uniform ring of mass M & radius R is placed directly above a uniform...
A uniform ring of mass M is a circular object with a constant mass distribution along its circumference. This means that the mass is evenly distributed throughout the ring, so each small segment of the ring has the same mass.
To calculate the mass of the ring, we can use the formula for the mass of a uniform object:
Mass = density * volume
In this case, the density is the mass per unit length, and the volume is the length of the ring multiplied by its cross-sectional area.
Since the ring is uniform, the length of the ring is equal to its circumference, which is given by the formula:
Circumference = 2 * π * radius
The cross-sectional area of the ring is given by the formula:
Area = π * (radius^2)
Now, we can substitute these formulas into the mass formula:
Mass = density * volume
= density * (Circumference * Area)
= density * (2 * π * radius) * (π * (radius^2))
= 2 * π^2 * density * (radius^3)
Therefore, the mass of the uniform ring is given by the formula:
Mass = 2 * π^2 * density * (radius^3)
Note that this formula assumes that the density is constant along the length of the ring. If the density varies, then this formula may not be accurate.
To calculate the mass of the ring, we can use the formula for the mass of a uniform object:
Mass = density * volume
In this case, the density is the mass per unit length, and the volume is the length of the ring multiplied by its cross-sectional area.
Since the ring is uniform, the length of the ring is equal to its circumference, which is given by the formula:
Circumference = 2 * π * radius
The cross-sectional area of the ring is given by the formula:
Area = π * (radius^2)
Now, we can substitute these formulas into the mass formula:
Mass = density * volume
= density * (Circumference * Area)
= density * (2 * π * radius) * (π * (radius^2))
= 2 * π^2 * density * (radius^3)
Therefore, the mass of the uniform ring is given by the formula:
Mass = 2 * π^2 * density * (radius^3)
Note that this formula assumes that the density is constant along the length of the ring. If the density varies, then this formula may not be accurate.
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A uniform ring of mass M & radius R is placed directly above a uniform sphere of mass 8M & radius R. The centre of ring is at a distance of d=√3R from the centre of the sphere. The gravitational attraction between the sphere and ring is
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A uniform ring of mass M & radius R is placed directly above a uniform sphere of mass 8M & radius R. The centre of ring is at a distance of d=√3R from the centre of the sphere. The gravitational attraction between the sphere and ring is for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A uniform ring of mass M & radius R is placed directly above a uniform sphere of mass 8M & radius R. The centre of ring is at a distance of d=√3R from the centre of the sphere. The gravitational attraction between the sphere and ring is covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform ring of mass M & radius R is placed directly above a uniform sphere of mass 8M & radius R. The centre of ring is at a distance of d=√3R from the centre of the sphere. The gravitational attraction between the sphere and ring is.
A uniform ring of mass M & radius R is placed directly above a uniform sphere of mass 8M & radius R. The centre of ring is at a distance of d=√3R from the centre of the sphere. The gravitational attraction between the sphere and ring is for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A uniform ring of mass M & radius R is placed directly above a uniform sphere of mass 8M & radius R. The centre of ring is at a distance of d=√3R from the centre of the sphere. The gravitational attraction between the sphere and ring is covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform ring of mass M & radius R is placed directly above a uniform sphere of mass 8M & radius R. The centre of ring is at a distance of d=√3R from the centre of the sphere. The gravitational attraction between the sphere and ring is.
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