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A helicopter flying at 20 m/s horizontally drops a 
rescue bag. Ignoring air resistance & taking g = 10
, the displacement of the bag 5 seconds after the
drop began is nearly
- a)100 m
- b)125 m
- c)160 m
- d)225 m
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A helicopter flying at 20 m/s horizontally drops arescue bag. Ignoring...
And assuming the bag falls vertically, the bag will accelerate downwards at a rate of 9.8 m/s^2 (acceleration due to gravity).
Using the formula for distance traveled under constant acceleration:
d = 1/2at^2
where d is the distance, a is the acceleration, and t is the time,
we can calculate the time it takes for the bag to reach the ground:
d = 1/2at^2
d = 1/2(9.8)(t^2)
d = 4.9t^2
When the bag is dropped, it has an initial velocity of 0 m/s in the vertical direction. The final velocity when it hits the ground will be the maximum velocity it reaches due to gravity, which we can calculate using the formula:
vf = vi + at
where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.
Since the bag is dropped from rest, vi = 0, so:
vf = at
vf = 9.8t
We can now use the fact that the horizontal velocity of the helicopter does not affect the vertical motion of the bag, and the time it takes for the bag to fall to the ground is the same as the time it takes for the helicopter to travel a horizontal distance of 20 meters.
Using the formula for distance traveled at constant velocity:
d = vt
where d is the distance, v is the velocity, and t is the time,
we can solve for t:
20 = 20t
t = 1 second
Therefore, the bag will hit the ground after 1 second of falling, and its final velocity will be:
vf = 9.8(1)
vf = 9.8 m/s
Note that if the bag were dropped from a higher altitude, it would take longer to reach the ground and would have a higher final velocity due to the longer time of acceleration.
Using the formula for distance traveled under constant acceleration:
d = 1/2at^2
where d is the distance, a is the acceleration, and t is the time,
we can calculate the time it takes for the bag to reach the ground:
d = 1/2at^2
d = 1/2(9.8)(t^2)
d = 4.9t^2
When the bag is dropped, it has an initial velocity of 0 m/s in the vertical direction. The final velocity when it hits the ground will be the maximum velocity it reaches due to gravity, which we can calculate using the formula:
vf = vi + at
where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.
Since the bag is dropped from rest, vi = 0, so:
vf = at
vf = 9.8t
We can now use the fact that the horizontal velocity of the helicopter does not affect the vertical motion of the bag, and the time it takes for the bag to fall to the ground is the same as the time it takes for the helicopter to travel a horizontal distance of 20 meters.
Using the formula for distance traveled at constant velocity:
d = vt
where d is the distance, v is the velocity, and t is the time,
we can solve for t:
20 = 20t
t = 1 second
Therefore, the bag will hit the ground after 1 second of falling, and its final velocity will be:
vf = 9.8(1)
vf = 9.8 m/s
Note that if the bag were dropped from a higher altitude, it would take longer to reach the ground and would have a higher final velocity due to the longer time of acceleration.
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Community Answer
A helicopter flying at 20 m/s horizontally drops arescue bag. Ignoring...
C... vertical distance = 125 and horizaontal distance= 100..so by pythagorus we got displacement
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Question Description
A helicopter flying at 20 m/s horizontally drops arescue bag. Ignoring air resistance & taking g = 10, the displacement of the bag 5 seconds after thedrop began is nearly a)100 mb)125 mc)160 md)225 mCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A helicopter flying at 20 m/s horizontally drops arescue bag. Ignoring air resistance & taking g = 10, the displacement of the bag 5 seconds after thedrop began is nearly a)100 mb)125 mc)160 md)225 mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A helicopter flying at 20 m/s horizontally drops arescue bag. Ignoring air resistance & taking g = 10, the displacement of the bag 5 seconds after thedrop began is nearly a)100 mb)125 mc)160 md)225 mCorrect answer is option 'C'. Can you explain this answer?.
A helicopter flying at 20 m/s horizontally drops arescue bag. Ignoring air resistance & taking g = 10, the displacement of the bag 5 seconds after thedrop began is nearly a)100 mb)125 mc)160 md)225 mCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A helicopter flying at 20 m/s horizontally drops arescue bag. Ignoring air resistance & taking g = 10, the displacement of the bag 5 seconds after thedrop began is nearly a)100 mb)125 mc)160 md)225 mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A helicopter flying at 20 m/s horizontally drops arescue bag. Ignoring air resistance & taking g = 10, the displacement of the bag 5 seconds after thedrop began is nearly a)100 mb)125 mc)160 md)225 mCorrect answer is option 'C'. Can you explain this answer?.
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