NEET Exam  >  NEET Questions  >  The total kinetic energy [ in joules] of the ... Start Learning for Free
The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is?
Most Upvoted Answer
The total kinetic energy [ in joules] of the molecules in 8g of methan...
Total Kinetic energy = n(3/2 RT0)
Where, n = Number of moles of the gas
R = Gas constant
T = Absolute Temperature
Molecular weight of Methane ,
CH4 = 12 + 4 *1 = 16
Therefore, number of moles of methane in 8g of methane,
= 8.0/16.0 =0.5
R = 8.314 joules/K/mole
T = 27+273 = 300K
Therefore ,Total kinetic of the molecules in 8g of methane at 300 K is
= Inl *3/2 RT
= 0.5*3/2*8.314*300
= 1870.65 joules
Avg. Kinetic energy = 1870.65/6.023*10^23 *0.5= 6.21 *10^-21 joules/molecules
Community Answer
The total kinetic energy [ in joules] of the molecules in 8g of methan...
Introduction:
In order to calculate the total kinetic energy of the molecules in 8g of methane at 27 degrees Celsius, we need to consider the formula for kinetic energy and the properties of methane.

Formula for kinetic energy:
The formula for kinetic energy is given by:
KE = 1/2 * m * v^2
where KE is the kinetic energy, m is the mass, and v is the velocity of the particles.

Properties of methane:
Methane (CH4) is a simple hydrocarbon gas. Its molar mass is approximately 16.04 g/mol. We can use this information to calculate the number of moles present in 8g of methane.

Calculating the number of moles:
To calculate the number of moles, we can use the formula:
moles = mass / molar mass

Given that the mass of methane is 8g and the molar mass is 16.04 g/mol, we can substitute these values into the formula:
moles = 8g / 16.04 g/mol = 0.498 mol

Calculating the velocity:
To calculate the velocity, we can use the formula:
v = sqrt(3 * RT / m)
where R is the ideal gas constant and T is the temperature in Kelvin.

Given that the temperature is 27 degrees Celsius, we need to convert it to Kelvin:
T(K) = T(C) + 273.15 = 27 + 273.15 = 300.15 K

Using the value of the ideal gas constant R = 8.314 J/(mol·K) and the molar mass of methane m = 16.04 g/mol, we can substitute these values into the formula:
v = sqrt(3 * 8.314 J/(mol·K) * 300.15 K / 16.04 g/mol) = 1561.7 m/s

Calculating the kinetic energy:
Now that we have the mass and velocity, we can substitute these values into the formula for kinetic energy:
KE = 1/2 * m * v^2
KE = 1/2 * 0.498 mol * (1561.7 m/s)^2

Calculating the kinetic energy gives us the answer in joules.

Conclusion:
The total kinetic energy of the molecules in 8g of methane at 27 degrees Celsius is calculated using the formula for kinetic energy, considering the properties of methane. The final result will depend on the specific calculations performed.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is?
Question Description
The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is?.
Solutions for The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is? defined & explained in the simplest way possible. Besides giving the explanation of The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is?, a detailed solution for The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is? has been provided alongside types of The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is? theory, EduRev gives you an ample number of questions to practice The total kinetic energy [ in joules] of the molecules in 8g of methane at 27 degree Celsius is? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev