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An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of communication satellite. Time period of revolution of X is (1)3 hours (2)6hours (3)4 days (4)72 days Solve it?
Most Upvoted Answer
An earth satellite X is revolving around earth in an orbit whose radiu...
Use T² directly proportional to R³ by Kepler's law
(24/t)²=[r÷(r/4)]³
(24/t)²=64
t=3hrs
(24/t)²=[r÷(r/4)]³
(24/t)²=64
t=3hrs
Community Answer
An earth satellite X is revolving around earth in an orbit whose radiu...
Given information:
- The radius of the orbit of the communication satellite = R
- The radius of the orbit of satellite X = R/4
To find:
The time period of revolution of satellite X
Solution:
The time period of revolution of a satellite can be determined using Kepler's Third Law of Planetary Motion, which states that the square of the orbital period of a planet is proportional to the cube of its average distance from the Sun.
Step 1: Identifying the key information:
- Radius of orbit of communication satellite = R
- Radius of orbit of satellite X = R/4
Step 2: Finding the ratio of the radii:
The ratio of the radii of satellite X to the communication satellite can be calculated as follows:
Ratio = (R/4) / R = 1/4
Step 3: Determining the ratio of the time periods:
Using Kepler's Third Law, we know that the square of the orbital period is proportional to the cube of the average distance. Therefore, the ratio of the time periods can be calculated as follows:
Ratio = (1/4)^(3/2) = 1/8
Step 4: Finding the time period of satellite X:
Since we know the time period of the communication satellite, we can use the ratio obtained in Step 3 to determine the time period of satellite X:
Time period of satellite X = (1/8) * time period of communication satellite
Step 5: Converting the time period into hours:
- The time period of the communication satellite is given in days.
- We need to convert the time period of satellite X to hours.
Step 6: Calculating the time period of satellite X:
- Let's assume the time period of the communication satellite is 1 day (to simplify the calculation).
- Time period of satellite X = (1/8) * 1 day = 1/8 day
- Since 1 day = 24 hours, the time period of satellite X = (1/8) * 24 hours = 3 hours
Step 7: Answer:
Therefore, the time period of revolution of satellite X is 3 hours.
Summary:
- The ratio of the radii of satellite X to the communication satellite is 1/4.
- The ratio of the time periods of satellite X to the communication satellite is 1/8.
- Assuming the time period of the communication satellite is 1 day, the time period of satellite X is 3 hours.
- The radius of the orbit of the communication satellite = R
- The radius of the orbit of satellite X = R/4
To find:
The time period of revolution of satellite X
Solution:
The time period of revolution of a satellite can be determined using Kepler's Third Law of Planetary Motion, which states that the square of the orbital period of a planet is proportional to the cube of its average distance from the Sun.
Step 1: Identifying the key information:
- Radius of orbit of communication satellite = R
- Radius of orbit of satellite X = R/4
Step 2: Finding the ratio of the radii:
The ratio of the radii of satellite X to the communication satellite can be calculated as follows:
Ratio = (R/4) / R = 1/4
Step 3: Determining the ratio of the time periods:
Using Kepler's Third Law, we know that the square of the orbital period is proportional to the cube of the average distance. Therefore, the ratio of the time periods can be calculated as follows:
Ratio = (1/4)^(3/2) = 1/8
Step 4: Finding the time period of satellite X:
Since we know the time period of the communication satellite, we can use the ratio obtained in Step 3 to determine the time period of satellite X:
Time period of satellite X = (1/8) * time period of communication satellite
Step 5: Converting the time period into hours:
- The time period of the communication satellite is given in days.
- We need to convert the time period of satellite X to hours.
Step 6: Calculating the time period of satellite X:
- Let's assume the time period of the communication satellite is 1 day (to simplify the calculation).
- Time period of satellite X = (1/8) * 1 day = 1/8 day
- Since 1 day = 24 hours, the time period of satellite X = (1/8) * 24 hours = 3 hours
Step 7: Answer:
Therefore, the time period of revolution of satellite X is 3 hours.
Summary:
- The ratio of the radii of satellite X to the communication satellite is 1/4.
- The ratio of the time periods of satellite X to the communication satellite is 1/8.
- Assuming the time period of the communication satellite is 1 day, the time period of satellite X is 3 hours.
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An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of communication satellite. Time period of revolution of X is (1)3 hours (2)6hours (3)4 days (4)72 days Solve it?
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An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of communication satellite. Time period of revolution of X is (1)3 hours (2)6hours (3)4 days (4)72 days Solve it? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of communication satellite. Time period of revolution of X is (1)3 hours (2)6hours (3)4 days (4)72 days Solve it? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of communication satellite. Time period of revolution of X is (1)3 hours (2)6hours (3)4 days (4)72 days Solve it?.
An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of communication satellite. Time period of revolution of X is (1)3 hours (2)6hours (3)4 days (4)72 days Solve it? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of communication satellite. Time period of revolution of X is (1)3 hours (2)6hours (3)4 days (4)72 days Solve it? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of communication satellite. Time period of revolution of X is (1)3 hours (2)6hours (3)4 days (4)72 days Solve it?.
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