NEET Exam > NEET Questions > The mass of glucose that would be dissolved i...
Start Learning for Free
The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is?
Verified Answer
The mass of glucose that would be dissolved in 50g of water in order t...
1 g of urea is 60 times less than its MW. Mass of glucose required should also be 60 times less, that is 180g /60 = 3 g
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
The mass of glucose that would be dissolved in 50g of water in order t...
Calculation of Mass of Glucose to produce the same lowering of vapour pressure
In order to calculate the mass of glucose that would be dissolved in 50g of water to produce the same lowering of vapour pressure as 1g of Urea in the same quantity of water, we can use the formula:
$\Delta P = i \cdot K_f \cdot m$
Where:
- $\Delta P$ = lowering of vapour pressure
- i = Van't Hoff factor (1 for glucose and 1 for urea)
- $K_f$ = cryoscopic constant for water (1.86 °C kg/mol)
- m = molality of the solution
Calculating Molality of Urea solution
Given that 1g of Urea is dissolved in 50g of water, we first need to calculate the molality of the Urea solution:
Molar mass of Urea (CH4N2O) = 60 g/mol
Number of moles of Urea = 1g / 60 g/mol = 0.0167 mol
Mass of water = 50g
Molality = moles of solute / mass of solvent (in kg) = 0.0167 mol / 0.05 kg = 0.334 mol/kg
Calculating Mass of Glucose
Now, we can use the molality of the Urea solution to calculate the mass of glucose that would produce the same lowering of vapour pressure:
$\Delta P_{Urea} = \Delta P_{Glucose}$
$i \cdot K_f \cdot m_{Urea} = i \cdot K_f \cdot m_{Glucose}$
$0.334 \cdot 1.86 = 1 \cdot 1.86 \cdot m_{Glucose}$
$m_{Glucose} = 0.334$
Therefore, the mass of glucose that would need to be dissolved in 50g of water to produce the same lowering of vapour pressure as 1g of Urea is 0.334g.
In order to calculate the mass of glucose that would be dissolved in 50g of water to produce the same lowering of vapour pressure as 1g of Urea in the same quantity of water, we can use the formula:
$\Delta P = i \cdot K_f \cdot m$
Where:
- $\Delta P$ = lowering of vapour pressure
- i = Van't Hoff factor (1 for glucose and 1 for urea)
- $K_f$ = cryoscopic constant for water (1.86 °C kg/mol)
- m = molality of the solution
Calculating Molality of Urea solution
Given that 1g of Urea is dissolved in 50g of water, we first need to calculate the molality of the Urea solution:
Molar mass of Urea (CH4N2O) = 60 g/mol
Number of moles of Urea = 1g / 60 g/mol = 0.0167 mol
Mass of water = 50g
Molality = moles of solute / mass of solvent (in kg) = 0.0167 mol / 0.05 kg = 0.334 mol/kg
Calculating Mass of Glucose
Now, we can use the molality of the Urea solution to calculate the mass of glucose that would produce the same lowering of vapour pressure:
$\Delta P_{Urea} = \Delta P_{Glucose}$
$i \cdot K_f \cdot m_{Urea} = i \cdot K_f \cdot m_{Glucose}$
$0.334 \cdot 1.86 = 1 \cdot 1.86 \cdot m_{Glucose}$
$m_{Glucose} = 0.334$
Therefore, the mass of glucose that would need to be dissolved in 50g of water to produce the same lowering of vapour pressure as 1g of Urea is 0.334g.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is?
Question Description
The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is?.
The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is?.
Solutions for The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? defined & explained in the simplest way possible. Besides giving the explanation of
The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is?, a detailed solution for The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? has been provided alongside types of The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? theory, EduRev gives you an
ample number of questions to practice The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of Urea in the same quantity of water is? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup