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The tank at a water supply station is filled with water by several pumps. At first three pumps of Ihe same capacity are turned on: 2.5 hours later, two more pumps (both the same) of a different capacity are set into operation. After 1 hour, the additional pumps were set into operation; the tank was almost filled to its capacity (15 m3 were still lacking): in another hour the tank was full. One of the two additional pumps could have filled the tank in 40 hours


Q. What is the volume of the tank?

  • a)
    60 m3

  • b)
    80 m3

  • c)
    75 m3

  • d)
    90 m3

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Read the passage below and solve the questions based on it.The tank at...
Let us assume that, first three pumps fills the tank in x hours .


so,


→ Efficiency of each pump = (1/x) m³ / hour .


then,


→ Efficiency of three pump = (3/x) m³ / hour .


 


now,


→ First three pumps works for = 2.5h + 1h + 1h = 4.5 hours.


 


so,


→ Water filled by 3 pumps in 4.5 hours = 4.5 * (3/x) = (13.5/x) m³ .


 


now, given that,


→ Time taken by additional pump to fill the tank = 40 hours.


so,


→ Efficiency of 2 additional tanks = 2 * (1/40) = (1/20) m³ / h .


 


and,


→ Additional pumps work for = 1 + 1 = 2 hours.


 


so,


→ Water filled by additional pumps in 2 hours = 2 * (1/20) = (1/10) m³ .


 


therefore,


→ (13.5/x) + (1/10) = 1


→ (13.5/x) = 1 - (1/10)


→ (13.5/x) = (9/10)


→ x = 135/9 = 15 hours.


 


since given that, in last 1 hour they filled 15 m³ .


 


hence,


→ 3 * (1/15) + (1/20) = 15 m³


→ (1/5) + (1/20) = 15


→ (4 + 1)/20 = 15


→ (5/20) = 15


→ (1/4) = 15


→ 1 = 60  (Ans.) (Option A)
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Most Upvoted Answer
Read the passage below and solve the questions based on it.The tank at...
From the solution provided it's clear that the question has a printing mistake , 15m^3 is lacking.

that's why after getting the value of 'x'  one can easily figure out that fraction of tank filled in last hour is 1/4 which is 15m3. So full tank will be 60m3
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Community Answer
Read the passage below and solve the questions based on it.The tank at...
Calculation:

Let us assume that the capacity of each pump of the first three pumps is 'x' and the capacity of each pump of the last two pumps is 'y'.

Let the volume of the tank be 'V'.

In the first 2.5 hours, the three pumps filled = 2.5x

After 2.5 hours, the five pumps filled (2.5x) + (2y)

In the next 1 hour, the five pumps filled 3.5x + 2y

The tank was almost filled to its capacity (15m3 were still lacking)

Therefore, (V-15) = 3.5x + 2y ----(1)

In the next one hour, the tank was full. Therefore,

V = 4.5x + 2y ----(2)

Given that one of the two additional pumps could have filled the tank in 40 hours.

Therefore, the capacity of each pump of the last two pumps = V/80 (Since one pump can fill the tank in 40 hours, two pumps can fill it in 20 hours. Therefore, the capacity of two pumps = V/20)

Substituting this in equation (2), we get

V = 4.5x + 2(V/80)

Multiplying both sides by 80, we get

80V = 360x + 2V

78V = 360x

V = 360x/78

Substituting this value in equation (1), we get

(360x/78) - 15 = 3.5x + 2(V/80)

Simplifying this, we get

x = 1.2

Substituting this value in equation (2), we get

V = 4.5(1.2) + 2(V/80)

Simplifying this, we get

V = 60

Therefore, the volume of the tank is 60 m3.

Hence, the correct answer is option (a).
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Read the passage below and solve the questions based on it.The tank at a water supply station is filled with water by several pumps. At firstthree pumps of Ihe same capacity are turned on: 2.5 hours later, two more pumps (both the same) of a different capacity are set into operation. After 1 hour, the additional pumps were set into operation; the tank was almost filled to its capacity (15 m3were still lacking): in another hour the tank was full. One of the two additional pumps could have filled the tank in 40 hoursQ. What is the volume of the tank?a)60 m3b)80 m3c)75 m3d)90 m3Correct answer is option 'A'. Can you explain this answer?
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