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The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The product of two numbers is 2028 and their H.C.F. is 13. The number ...
Let the numbers 13a and 13b.
Then, 13a * 13b = 2028
=>ab = 12.
Now, the co-primes with product 12 are (1, 12) and (3, 4).
[Note: Two integers a and b are said to be co prime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.
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Most Upvoted Answer
The product of two numbers is 2028 and their H.C.F. is 13. The number ...
Solution:

Given, the product of two numbers is 2028 and their H.C.F. is 13.
Let the two numbers be 13a and 13b (where a and b are co-primes)
Therefore, 13a × 13b = 2028
=> ab = 12
So, the possible pairs of (a, b) are (1, 12) and (3, 4)
Hence, the possible pairs of numbers are (13 × 1, 13 × 12) and (13 × 3, 13 × 4)
Therefore, there are two pairs of numbers whose product is 2028 and H.C.F. is 13.

Therefore, option 'B' is the correct answer.
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The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:a)1b)2c)3d)4Correct answer is option 'B'. Can you explain this answer?
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