Solution:

To determine the mass of iodine in the solution, we need to use the equilibrium concentration and the molar mass of iodine.

Given:
- Mass of iodine (I2) = 0.200g
- Volume of water = 100 ml = 0.1 L
- Equilibrium concentration of I2 ([I2]equilibrium) = 0.0011 mol/L

Step 1: Calculate the moles of I2
The moles of I2 can be calculated using the formula:
moles = mass / molar mass

The molar mass of iodine (I2) is approximately 253.8 g/mol.
Using the given mass of iodine:
moles of I2 = 0.200g / 253.8 g/mol
moles of I2 = 0.000788 mol

Step 2: Calculate the initial concentration of I2
The initial concentration of I2 can be calculated using the formula:
initial concentration = moles / volume

Using the given volume of water:
initial concentration of I2 = 0.000788 mol / 0.1 L
initial concentration of I2 = 0.00788 mol/L

Step 3: Calculate the change in concentration
The change in concentration can be calculated by subtracting the equilibrium concentration from the initial concentration:
change in concentration of I2 = equilibrium concentration - initial concentration
change in concentration of I2 = 0.0011 mol/L - 0.00788 mol/L
change in concentration of I2 = -0.00678 mol/L

Step 4: Calculate the mass of I2 in solution
The mass of I2 in solution can be calculated using the formula:
mass = moles * molar mass

Using the change in concentration:
moles of I2 = change in concentration * volume
moles of I2 = -0.00678 mol/L * 0.1 L
moles of I2 = -0.000678 mol

mass of I2 = -0.000678 mol * 253.8 g/mol
mass of I2 = -0.172 g

Step 5: Interpretation of the result
The calculated mass of iodine is -0.172 g. However, since mass cannot be negative, it indicates that there was an error in the calculations or an assumption made.

It is important to review the calculations and check for any mistakes or inconsistencies in the given information.